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aalyn [17]
3 years ago
14

HURRY!!! How is completing the square beneficial? (in quadratic equation)

Mathematics
1 answer:
givi [52]3 years ago
7 0
"Completing the square" is a step in the solution of quadratic equations. It can be accomplished without the guesswork or trial-and-error associated with methods like factoring, and it always leads to a solution. It is the method by which the quadratic formula is derived.
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Write an equation of the line that passes through the given point and is parallel to the graph of the given equation.
True [87]
Question 1:

--------------------------------------------------------------------
Find Slope
--------------------------------------------------------------------
Equation: y = 5x - 2
Slope = 5
Slope of parallel line = 5

--------------------------------------------------------------------
Insert slope into the general equation y = mx + c
--------------------------------------------------------------------
y = 5x + c

--------------------------------------------------------------------
Find y-intercept
--------------------------------------------------------------------
At point (2, -1)
y = 5x + c
-1 = 5(2) + c
c = -1 - 10
c = -11

--------------------------------------------------------------------
Insert y-intercept into the equation
--------------------------------------------------------------------
y = 5x + c
y = 5x - 11

--------------------------------------------------------------------
Answer: y = 5x - 11
--------------------------------------------------------------------

Question 2:

--------------------------------------------------------------------
Find Slope
--------------------------------------------------------------------
y = 9x 
Slope = 9 
Slope of the parallel line = 9

--------------------------------------------------------------------
Insert slope into the equation y = mx + c
--------------------------------------------------------------------
y = 9x + c

--------------------------------------------------------------------
Find y-intercept
--------------------------------------------------------------------
y = 9x + c
At point (0, 5)
5 = 9(0) + c
c = 5

--------------------------------------------------------------------
Insert y-intercept into the equation
--------------------------------------------------------------------
y = 9x + c
y = 9x + 5

--------------------------------------------------------------------
Answer: y = 9x + 5
--------------------------------------------------------------------
7 0
3 years ago
2/3b+5=20−b Solve for b. Both sides have to be equal.
BigorU [14]

Answer:

B=9

Step-by-step explanation:

Solve for  b  by simplifying both sides of the equation, then isolating the variable.

Hope this helps

3 0
3 years ago
Read 2 more answers
What is the value of 125 ⅔ ?​
horrorfan [7]

Answer:125.666

Step-by-step explanation:

8 0
2 years ago
Determine whether is a right triangle for the given vertices. Explain. Q(7, –10), R(–3, 0), S(9, –8)
andriy [413]

Answer:

Yes, It is a right triangle for the given vertices.

Step-by-step explanation:

Given:

Q(7, –10),

R(–3, 0),

S(9, –8)  

To Find:

determine whether is a rig ht triangle for the given vertices = ?

Solution:

QR=\sqrt{(-3-7)^2+(0-(-10))^2}

QR=\sqrt{(-10)^2+(10)^2}

QR=\sqrt{100+100}

QR=\sqrt{200}--------------------------(1)

QR=14.142136

RS=\sqrt{(9-(-3))^2+(-8-0)^2}

RS=\sqrt{(12)^2+(-8)^2}

RS=\sqrt{144+64}

RS=\sqrt{208}---------------------------(2)

RS=14.422205

QS=\sqrt{(7-9)^2+(-10-(-8))^2}

QS=\sqrt{(-2)^2+(-2)^2}

QS=\sqrt{4+4}

QS=\sqrt{8}-------------------------------------(3)

QS=2.828427

According to Pythagorean Theorem,

RS^2 = QR^ +QS^2

Substituting the values,

(\sqrt{208})^2 = (\sqrt{200})^2 +(\sqrt{8})^2

208 = 200 +8

208 = 208

Pythagorean theorem is satisfied. Hence it is a right triangle.

8 0
3 years ago
2. Samuel used clay to make a diorama of the pyramids in Ancient Egypt. He made two triangular pyramids and three rectangular py
zalisa [80]

Answer:

124.16 cubic meter of clay will be used to create all the pyramids

Step-by-step explanation:

The remaining part of the question is given in the attached file

Solution

The total clay used is equal to the sum of volumes of two triangular and three rectangular pyramids.

For Rectangular Pyramid,

Volume of three rectangular pyramids

3 * \frac{BH}{3} = BH

Substituting the given values in above equation, we get -

15.5 * 5 = 77.5 cubic centimeter

For triangular Pyramid,

Volume of two  triangular pyramids

2 * \frac{BH}{3}\\2 * \frac{10 * 7}{3}

46.67  cubic centimeter

Total clay used = Volume of 3 rectangular pyramid + volume of 2 triangular pyramid = 77.7 + 46.67 = 124.16 Cubic centimeter

5 0
2 years ago
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