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2 years ago

Help me out plz ????

Mathematics

1 answer:

kirill [66]2 years ago

5 0

96 cm^2

Each side has an area of 24 cm^2, so just multiply that by 4

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PLEASE HELP NEED THIS TO PASS

yaroslaw [1]

The solutions to f(x) = 64 is x = 7 and x = –7.

Solution:

Given data:

$$f(x)=x^{2}+15$ – – – – (1)

$f(x)=64$ – – – – (2)

To find the solutions to f(x) = 64.

Equate equation (1) and (2), we get

$x^2+15=64$

Subtract 15 from both sides of the equation.

$x^2+15-15=64-15$

$x^2=49$

$x^2=7^2$

Taking square root on both sides of the equation, we get

x = ±7

The solutions to f(x) = 64 is x = 7 and x = –7.

5 0

3 years ago

Kendall is solving this inequality. x/2 + 6 > 42 What should she do first to solve?

Aleonysh [2.5K]

Answer:

see below

Step-by-step explanation:

First, she should subtract 6 from both sides of the inequality. This makes it so that the x terms are on one side and the non-x terms are on the other side so she can then solve for x by multiplying the entire inequality by 2.

3 0

3 years ago

What is 12.345 rounded to the nearest tenth

noname [10]

Rounding to the nearest tenth means rounding to the decimal place directly to the right of the decimal.

The rules of rounding are fairly simple. If the number to the right of the number you are rounding is greater than or equal to 5, you round up. If the number to the right is less than 5, you round down.

Let's take a look at the number 12.345.
First, round to the hundredths place. The number right before the 4 is 5, so we round up. This gives us the number 12.35.
Next, we have to round to the tenths place. The number to the right of the 3 is 5, so we round up as well. This gives us the number 12.4.

Answer: 12.4

7 0

3 years ago

Read 2 more answers

Solve the linear equation x + 4 + 3 + 72

elixir [45]

Answer:

x=17

Step-by-step explanation

4x+4=72

-4 -4

4x=68

/4 /4

x= 17

7 0

2 years ago

Read 2 more answers

I don’t understand this and I did take notes on this on the computer but I still don’t understand it.

Serggg [28]

Answer:

I'[−3, −2], Q'[2, 0], ?'[0, 1], E'[−3, −1]

Step-by-step explanation:

The line of reflection is at y = −2, so looking at the line and where the coordinates of the shape are, you will have this:

I[−3, −2] → I'[−3, −2] (on the line, so it remains the same)

Q[2, −4] → Q'[2, 0]

?[0, −5] → ?'[0, 1]

E[−3, −3] → E'[−3, −1]

I am joyous to assist you anytime.

3 0

3 years ago