F(x) = 8x + 1
a) The slope is the number on the x which is 8
b) y-intercept is added (or subtracted) to the x which is 1
c) f(0) = 8(0) + 1 = 1
d) 9 = 8x + 1
8 = 8x
x = 1 - solution
(1, 9) - ordered pair
e)
-7 <= 8x + 1
-8 <= 8x
-1 <= x
{x | x => -1}
I'll let you graph f(x)
Answer:
x = 13, y = 26
The length of the sides of Δ QRS are QR = 104, <u>QS = 468</u>, RS = 76
Step-by-step explanation:
In ΔRQS
∵ M is the mid-point of side RQ
→ That means M divide RQ into 2 equal parts RM and MQ
∴ RM = MQ
∵ RM = 4x
∵ MQ = 52
→ Equate them
∴ 4x = 52
→ Divide both sides by 4 to get x
∴ x = 13
∵ P is the mid-point of side QS
→ That means P divide QS into 2 equal parts QP and PS
∴ QP = PS
∵ QP = 9y
∵ PS = 234
→ Equate them
∴ 9y = 234
→ Divide both sides by 9 to get y
∴ y = 26
→ Find the length of each side
∵ RQ = 52 + 52
∴ RQ = 104
∵ QS = 234 + 234
∴ QS = 468
∵ RS = 38 + 38
∴ RS = 76
∴ The length of the sides of Δ QRS are QR = 104, QS = 468, RS = 76
Note: PS = 234 is wrong because it made the length of the sides QS = 468, which could not be because the sum of any 2 sides of a triangle must be greater than the 3rd side. So check it.
The answer is 8 by itself i think
Answer:
c) 345.4 cm²
The plastic coating would be needed to coat the surface of the chain link
= 345.4 cm²
Step-by-step explanation:
<em>Given radius of the cylinder 'r' = 2.5 cm</em>
<em>Given Height of the cylinder 'h' = 22 cm</em>
<em>Area of the curved surface = 2 π r h </em>
<em>The plastic coating would be needed to coat the surface of the chain link</em>
<em> A = 2 π r h </em>
<em> A = 2 × 3.14 ×2.5×22 </em>
<em> A = 345.4 cm²</em>
<u><em>Conclusion</em></u><em>:-</em>
<em>The plastic coating would be needed to coat the surface of the chain link</em>
<em> = 345.4 cm²</em>
The answer is 14/15 because we need to make the denominators the same before adding the numerators. It's all about finding the lowest common denominator which is 15. :)
