ANYONE PLS HELP!!! ASAP!!!

on a piece of paper, graph y<-3/4x+2. Then determine which answer choice matches the graph you drew.

exis [7]

Answer:

D. Graph D

Step-by-step explanation:

The "y <" tells you two things: (1) shading will be below the line, where y-values are less than those on the line, and (2) the line will be dashed, because the "equal to" case is not included.

Only one graph has a dashed line with shading below: Graph D.

7 0

2 years ago

How do you find the perimeter of a triangle using one side length and two angles of 60 degrees

Licemer1 [7]

Give me a picture of the problem and i will solve it

8 0

2 years ago

Find a numerical value if one trigonometric function of x if tan2x-sin2x/sin2x=5

seropon [69]

Answer:

The values of x that satisfy the given equation are:

x1 = 1.183 + nπ

x2 = -1.183 + nπ

Step-by-step explanation:

Given tan²x - sin²x/sin²x = 5

Simplifying this, we have

tan²x - 1 = 5

Adding 1 to both sides, we have

tan²x = 6

Because tan²x = (tanx)², we can write as

(tanx)² = 6

Taking square roots of both sides, we have.

tanx = ±√6

x = arctan(±√6) + nπ

≈ 1.183 + nπ or -1.183 + nπ

4 0

2 years ago

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

KIM [24]

Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006$

All girls from the third group:

20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

7 0

2 years ago

Jerry buys a case of bar soap. The case holds 12 packages. Each package contains four bars of soap. If each bar of soap is four

Sonja [21]

Answer:

The answer is D. 12 pounds

Step-by-step explanation:

Math is not my strong suit, so I apologize if this is wrong.

7 0

2 years ago