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Inessa [10]
3 years ago
12

Solve each of the following equations for x. 2^x − 1 = 0

Mathematics
1 answer:
AlekseyPX3 years ago
3 0

Answer:

The solution to the equation is x = 0

Step-by-step explanation:

Hi there!

First, let´s write the equation:

2ˣ - 1 = 0

To solve it for x, let´s add 1 to both sides of the equation:

2ˣ = 1

Apply log to both sides of the equation

log(2ˣ) = log(1)

Apply logrithm property: log(2ˣ) = x log(2)

x log(2) = log(1)

x log(2) = 0

x = 0

The solution is x = 0

Let´s check the solution:

2ˣ - 1 = 0

x = 0

2⁰ - 1 = 0

1 - 1  = 0

0 = 0

The solution is correct!

Have a nice day!

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If a=2 and b=3, then the limit from the right would be 2+3=5\neq2, so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation a+b=2.

Part (c) is done similarly to part (1). This time, you need to limits from either side as x\to2 to match. You have

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