18 - (9 x 14) This equation represents the sentence.
hope that helps :)
Answer:
a) Interval containing the corresponding P-value for a two-tailed test is;
0.01 ≤ p-value ≤ 0.02
b) Interval containing the corresponding P-value for a right-tailed
test is;
0.005 < p-value < 0.010
Step-by-step explanation:
Given the data in the question;
t = 2.930
df = 10
Test statistics;
Now form the t-distribution table, at df = 10, 2.930 falls between { t=2.764 and t=3.169]
so;
for a two tailed test, corresponding p-value is between: 0.02 and 0.01
For one(right) tailed test, corresponding p-value is between: 0.01 and 0.005
Therefore;
a) Interval containing the corresponding P-value for a two-tailed test is;
0.01 ≤ p-value ≤ 0.02
b) Interval containing the corresponding P-value for a right-tailed
test is;
0.005 < p-value < 0.010
Answer:
The second one
Step-by-step explanation:
The first car goes 30 miles on one gallon of gas and the second car goes 32 miles on one gallon of gas.
Answer:
D. x≥6
Step-by-step explanation:
If x²≥36
x≥√36
x≥6
Answer:
x = 32.6
Step-by-step explanation:
Please share the instructions: "Find the value of x ... " Also, indicate whether x is in the numerator or denominator.
If in the numerator, then we have (12.6/12)x = 34.2.
Multipying both sides by (12/12.6) yields 34.2(12/12.6), or x = 32.6
