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xxTIMURxx [149]

3 years ago

6

The time t required to drive a certain distance varies inversely with the speed r. If it takes 2 hours to drive the distance at

30 miles per hour, how long will it take to drive the same distance at 50 miles per hour?

2 answers:

TEA [102]3 years ago

8 0

It will take 70 hours

Stolb23 [73]3 years ago

3 0

Answer:

70

Step-by-step explanation:

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7 over 2 as a mixed number

ivanzaharov [21]

Answer:

3 1/2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Tony is trying to find the solution of the system 2x - 4y +12 using elimination 3x + 4y = 48 He wrote these steps to solve the p

kobusy [5.1K]

Answer: Solution: (12, 3)

Step-by-step explanation:

2x - 4y = 12

3x + 4y = 48

Add both equations

5x = 60

Divide both sides by 5

x = 12

We can use the value of x to find y

3x + 4y = 48

3 (12) + 4y = 48

36 + 4y = 48

Subtract 36 from both sides

4y = 12

Divide both sides by 4

y = 3

Solution: (12, 3)

7 0

3 years ago

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

so

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

3 0

3 years ago

50pts help! consider this quadratic equation. 2x^2-1=3x+4 Which equation correctly applies to the quadratic formula?

eduard

Step-by-step explanation:

im not going to go in to detail but the answer is c

7 0

3 years ago

Read 2 more answers

F(1)=-12, f(n)=2f(n-1) <br> find first 4 terms

amid [387]

<h3>First four terms are: -12, -24, -48, -96</h3>

============================================

Explanation:

The notation f(1) = -12 tells us that the first term is -12.

The equation f(n) = 2*f(n-1) indicates that we're multiplying the (n-1)th term by 2 to get the nth term. Basically we multiply each term by 2 to get the next term.

-12*2 = -24

-24*2 = -48

-48*2 = -96

So the first four terms are -12, -24, -48, -96.

-----------------------------------

Alternative Approach

f(1) = -12 .... first term

f(n) = 2*f(n-1) ... nth term recursive formula

f(2) = 2*f(2-1) ... plug in n = 2

f(2) = 2*f(1)

f(2) = 2*(-12) ... plug in f(1) = -12

f(2) = -24 ... second term

f(n) = 2*f(n-1) .... resetting for the next computation

f(3) = 2*f(3-1) ... plug in n = 3

f(3) = 2*f(2)

f(3) = 2*(-24) ... plug in f(2) = -24

f(3) = -48 .... third term

f(n) = 2*f(n-1) ... one more reset

f(4) = 2*f(4-1) .... plug in n = 4

f(4) = 2*f(3)

f(4) = 2*(-48) ... plug in f(3) = -48

f(4) = -96 ... fourth term

We get the first four terms to be -12, -24, -48, -96, which was the same as earlier.

4 0

3 years ago