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Keith_Richards [23]
3 years ago
13

5x=72? A true or false question by my teacher! I need answers T-T

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
7 0

Answer:

Also you didn't say what the x is equaled to so i cant really answer this that easily but ill try

Step-by-step explanation:

If 5 times something ( X ) equals 72 then this would be false.

5 times anything is either ends with a 5 or a 0, And if i wrong then please tell me i didnt really get this question to much so I just tried ^-^

choli [55]3 years ago
4 0

Answer:

false

Step-by-step explanation:

i'm not sure but i think it's false

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The volume of a cube is V=s3 , where s is the length of one edge of the cube. What is the edge length s for each cube?
PolarNik [594]

Answer:

s = \sqrt[3]{999} }

Step-by-step explanation:

V = s^3

Plug in the given volume.

999 = s^3

Take the third root of both sides to cancel out the ^3.

\sqrt[3]{999} } = s

4 0
3 years ago
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A company bought 28 desks for each<br> of its 17 offices. How many desks were<br> bought altogether?
nika2105 [10]

Answer:

476

Step-by-step explanation:

THAT SHOULD BE 28*17 Wich is 476

8 0
2 years ago
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Explain the distance formula. Than use it to calculate the distance between A(1, 1) and B(7, -7).
Alina [70]
The answer is 10 units.

8 0
3 years ago
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Given g(x) = 3x + 3, find g(-6).
Strike441 [17]

Answer:

-15

Step-by-step explanation:

g(x) = 3x + 3

Let x = -6

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6 0
3 years ago
Show all work and reasoning
Natalija [7]
Split up the interval [2, 5] into n equally spaced subintervals, then consider the value of f(x) at the right endpoint of each subinterval.

The length of the interval is 5-2=3, so the length of each subinterval would be \dfrac3n. This means the first rectangle's height would be taken to be x^2 when x=2+\dfrac3n, so that the height is \left(2+\dfrac3n\right)^2, and its base would have length \dfrac{3k}n. So the area under x^2 over the first subinterval is \left(2+\dfrac3n\right)^2\dfrac3n.

Continuing in this fashion, the area under x^2 over the kth subinterval is approximated by \left(2+\dfrac{3k}n\right)^2\dfrac{3k}n, and so the Riemann approximation to the definite integral is

\displaystyle\sum_{k=1}^n\left(2+\frac{3k}n\right)^2\frac{3k}n

and its value is given exactly by taking n\to\infty. So the answer is D (and the value of the integral is exactly 39).
8 0
3 years ago
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