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tiny-mole [99]
4 years ago
8

How do you solve / figure 8 x 51 (Distributive property)

Mathematics
1 answer:
Step2247 [10]4 years ago
5 0
8(51)

=8(50+1)

=(8*50)+(8*1)

=(8*5*10)+(8*1)

=400+8

=408
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3 years ago
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What is 0.464646... as a fraction
rewona [7]

This is what I get


You have to place the decimal numbers over the power of 10.since its 6 places to the right will be 10^6(1000000).


464646/1000000


Now cancel common factors by factoring out 2.


232323/500000=0.464646

7 0
4 years ago
Lines x and y are parallel.
densk [106]

On the bottom line, the 106 and number 1 make a straight line and needs to equal 180 degrees.

This means number 1 = 180-106 = 74 degrees.

Because x and y are parallel, the top outside angle is the same as number 1.

6x +8 = 74

Subtract 8 from both sides:

6x = 66

divide both sides by 6:

x = 66 / 6

x = 11

Now you have x, replace x in the equation for 7x-2 to find that angle:

7(11) -2 = 77-2 = 75 degrees.

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7 0
3 years ago
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Find the zeroes of the following equation:
weqwewe [10]

Answer:  \bold{x=\dfrac{1\pm \sqrt5}{2}}

                both zeros are irrational numbers

<u>Step-by-step explanation:</u>

Note: The question would have made more sense if if it was 2/x = x - 1 but I will answer it as written.

\dfrac{1}{x}=x-1\qquad \text{Restriction: }x\neq 0\\\\\\\text{Cross multiply, simplify, and set equal to zero:}\\1=x(x-1)\\\\1=x^2-x\\\\0=x^2-x-1\\\\\\\text{This is not factorable so you will need to use Quadratic Formula:}\\\\x=\dfrac{-(-1)\pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}\\\\\\x=\dfrac{1\pm \sqrt5}{2}

7 0
3 years ago
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
4 years ago
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