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TEA [102]
2 years ago
7

Instructions: Given the following roots solve for the quadratic equation. Can I maybe get a hand on this one? My teacher didn't

explain well last class session and it's messing my brain none of us studied well for this.

Mathematics
1 answer:
Blizzard [7]2 years ago
7 0
Do you wanna graph or noi
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Factor Completely: 25x2 - 64 A) 5(x - 8)(x + 8) B) 5(x - 8)(x - 8) C) (5x - 8)(5x + 8) D) (25x - 1)(x + 64)
ZanzabumX [31]

Rewrite it in the form a^2 - b^2, where a = 5x and b = 8

(5x)^2 - 8^2

Use the Difference of Squares; a^2 - b^2 = (a + b)(a - b)

<u>= C. (5x - 8)(5x + 8)</u>

4 0
3 years ago
Toni had 5 1/2 kilograms of sugar.how many cakes can he bake if he ise 1/4 hilogram of sugar per cake?
allochka39001 [22]

Answer:

22 cakes

Step-by-step explanation:

5 1/2kg = 11/2 = 22/4

22/4 is what you have in sugar while you only need 1/4 per cake, so you can make 22 cakes

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3 years ago
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Help asap! Brainliest + a lot of points! <br><br> Answer and explain!
Alborosie

The three important about the box and whisker plot is that it shows median, LIQ (Low interquartile), UIQ (Upper Interquartile), the lowest and highest number

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3 years ago
Twelve times the sum of three and a number is equal to five times the sum of eight more then twice the number
Andreas93 [3]
The equation is 12(3+x)=5(2x+8)
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3 years ago
Suppose that a large mixing tank initially holds 100 gallons of water in which 50 pounds of salt have been dissolved. Another br
Serggg [28]

Answer:

dA/dt = 12 - 2A/(100 + t)

Step-by-step explanation:

The differential equation of this problem is;

dA/dt = R_in - R_out

Where;

R_in is the rate at which salt enters

R_out is the rate at which salt exits

R_in = (concentration of salt in inflow) × (input rate of brine)

We are given;

Concentration of salt in inflow = 4 lb/gal

Input rate of brine = 3 gal/min

Thus;

R_in = 4 × 3 = 12 lb/min

Due to the fact that solution is pumped out at a slower rate, thus it is accumulating at the rate of (3 - 2)gal/min = 1 gal/min

So, after t minutes, there will be (100 + t) gallons in the tank

Therefore;

R_out = (concentration of salt in outflow) × (output rate of brine)

R_out = [A(t)/(100 + t)]lb/gal × 2 gal/min

R_out = 2A(t)/(100 + t) lb/min

So, we substitute the values of R_in and R_out into the Differential equation to get;

dA/dt = 12 - 2A(t)/(100 + t)

Since we are to use A foe A(t), thus the Differential equation is now;

dA/dt = 12 - 2A/(100 + t)

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3 years ago
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