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Llana [10]
3 years ago
12

2. A rope is thrown over a beam, and one end is tied to a 300 N bundle of lumber. You pull the free end of the rope 2 m with a f

orce of 400 N to lift the lumber off the ground. How much work have you done?​
Mathematics
1 answer:
bonufazy [111]3 years ago
3 0

504 water resource of number of the lumber of the ground

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What value would be placed in the space shown to create a perfect square trinomial?
charle [14.2K]

Answer:

1st option 9/4

Step-by-step explanation:  Searched up the problem on brainly and this was the answer. Hope that helps

3 0
2 years ago
HELPP plz in. 17 thank u so much
sergij07 [2.7K]
In the table, you can see level 1 is 5 to the first power, level 2 is 5 to the second and go on. 
so in level 6 would be 5 to the sixth power
so the answer to first one is 5^6 
for the second question you should know that level 2 is 5^2 and level 6 is 5^6 so 5^6/5^2 = 5^4 is the answer :))))
I hope this is helpful
have a nice day
6 0
3 years ago
Points A B C D and E are collinear and in that order. Find AC if AE=x+50 and CE=x+32
Lana71 [14]

Answer:

18

Step-by-step explanation:

Points A B C D and E are collinear.

\therefore AE = AC + CE\\\therefore AC = AE - CE\\\therefore AC = x + 50 - (x + 32) \\\therefore AC = x + 50 - x - 32 \\\therefore AC =  50 - 32 \\ \huge \red{ \boxed{\therefore AC = 18}}

3 0
3 years ago
The radioactive element​ carbon-14 has a​ half-life of 5750 years. A scientist determined that the bones from a mastodon had los
Gnesinka [82]

The bones at the time they were​ discovered when the radioactive element​ carbon-14 has a​ half-life of total 5750 years are 10062.5-year-old.

<h3>What is half-lives?</h3>

Half lives is the time interval which is need to decay the atomic nuclei of a radioactive sample.

There is a scientist who determined that the bones from a mastodon had lost 70.3​% of their​ carbon-14.  Thus, the fraction remaining is,

f=1-(70.3/100)=1-0.703

f=1-(70.3/100)=0.297

Now the fraction remaining can be given as,

f=(1/2)ⁿ

Here, n is the half life elapsed. Put the value of fraction remaining.

0.297=(1/2)ⁿ

n=1.75

The radioactive element​ carbon-14 has a​ half-life of total 5750 years. Thus,

Years=1.75*5750

Years=10062.5

Thus, the bones at the time they were​ discovered when the radioactive element​ carbon-14 has a​ half-life of total 5750 years are 10062.5-year-old.

Learn more about the half lives here;

brainly.com/question/2320811

#SPJ1

6 0
2 years ago
I got 30 will someone double check me please.
Tpy6a [65]
That’s the correct answer
4 0
2 years ago
Read 2 more answers
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