Answer: Area of Parallelogram is 28 units squared.
Step-by-step explanation:
Knowing, any two vector sides of a parallelogram sharing the same initial point, we can find the area of parallelogram that two vectors are shaping, using the cross product of these two vectors a×b, where the area is given by
Area= |a×b| ___ (1)
From the given points,we may choose any three of them such and find a two vector and expresses the sides of parallelogram " or one side and a diagonal of parallelogram" ,we may choose for example B ,C and D.
Moreover, we may choose point B, to be common point for the two sides " the initial point of two vector" thus we need to find vector BD and vector BC .
Calculations are given in picture.
The value of x is 3, while the length of the rectangle is 30 units and the width is 24 units.
<h3>How to determine the dimensions?</h3>
The given parameters are:
Base = 5(x+3)
Height = 2(x+9)
Perimeter = 108
The perimeter of a rectangle is
P = 2 *(Base + Height)
So, we have:
2 *(5(x + 3) + 2(x + 9)) = 108
Divide both sides by 2
5(x + 3) + 2(x + 9) = 54
Open the brackets
5x + 15 + 2x + 18 = 54
Evaluate the like terms
7x = 21
Divide by 7
x = 3
Substitute x = 3 in Base = 5(x+3) and Height = 2(x+9)
Base = 5(3+3) = 30
Height = 2(3+9) = 24
Hence, the value of x is 3, while the length of the rectangle is 30 units and the width is 24 units.
Read more about perimeter at:
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1 = sin²0 + cos²0
sin²0 = 1 - cos²0
sin²0 = 1 - 11/36
sin²0 = 25/36
sin 0 = 5/6 or -5/6
In the first quadrant, the values for sin, cos and tan are positive.
sin0 = 5/6