A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:Her Aunt paid her 4.50 and hour and her neighbor 6 an hour. The difference is 1.5
Step-by-step explanation:
When you divide fractions, you want to use keep change flip.
You keep the 1st fraction, change the division sign into a multiplication sign, then flip the last fraction.
Let’s use 3/4 ÷ 2/3
Keep 3/4 the same, change the division sign into a multiplication sign, and flip 2/3 so that it is 3/2
It’ll look like this
3/4 x 3/2
Now just multiply the numerators, 2 x 3, then multiply the demoninators, 4 x 2.
You get 6/8
Simplify this number and you get 3/4.
If you have any further questions feel free to ask.
Hope this helps.
It should be for seconds...
30min(60sec/min)=1800s
