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avanturin [10]
3 years ago
9

Which relation is a function? A (3, 2), (2, 3), (4,5), (3, 4)

Mathematics
1 answer:
postnew [5]3 years ago
4 0

Answer:

(4,5)

Step-by-step explanation:

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What's the slope (0,4) and (-8,-1)
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slope = y2-y1 over x2-x1

-1 - 4= -5

-8-0 - -8

so you get -5/-8

negative divided by negative = positive

 slope = 5/8

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3 years ago
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At a bus stop station, buses deport at a rate of 3 every 10 minutes. At this rate how many buses would depart in one hour.
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If every 10 minutes 3 buses leave then over a course of 60 minutes (1 hour ) 18 buses would leave 
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What is the surface area of the square pyramid?
e-lub [12.9K]

Answer:

SA = 16 units^2

Step-by-step explanation:

B - base

H - height

SA - surface area

B = 2

H = 3

SA = (B × B) + 4((1/2)×(B × H))

SA = (2×2) + 4((1/2)×(2×3))

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7 0
3 years ago
The distance between the point (2,1,1) and the plane x-2y=5 is​
Eduardwww [97]

The given plane has normal vector

x-2y=5\implies\mathbf n=\langle1,-2,0\rangle

Scaling <em>n</em> by a real number <em>t</em> gives a set of vectors that span an entire line through the origin. Translating this line by adding the vector <2, 1, 1> makes it so that this line passes through the point (2, 1, 1). So this line has equation

\mathbf r(t)=\langle1,-2,0\rangle t+\langle2,1,1\rangle=\langle 2+t, 1-2t, 1\rangle

This line passes through (2, 1, 1) when <em>t</em> = 0, and the line intersects with the plane when

x-2y=5\implies(2+t)-2(1-2t)=5\implies5t=5\implies t=1

which corresponds the point (3, -1, 1) (simply plug <em>t</em> = 1 into the coordinates of \mathbf r(t)).

So the distance between the plane and the point is the distance between the points (2, 1, 1) and (3, -1, 1):

\sqrt{(2-3)^2+(1-(-1))^2+(1-1)^2}=\boxed{\sqrt5}

7 0
4 years ago
NEED HELP ASAP WILL MARK BRAINLIEST!!!!!!!!!!!!
olga2289 [7]

Answer:

b) -2

Step-by-step explanation:

The equation is in the form

y= mx+b  where m is the slope and b is the y intercept

y = -x-2

The slope is -1 and the y intercept is -2

3 0
3 years ago
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