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zzz [600]
1 year ago
9

Locate and plot √11 on a number line. Find a better approximation using decimals. 3.2×3.2= 3.4×3.4 = (Type integers or decimals.

)​

Mathematics
1 answer:
ki77a [65]1 year ago
8 0

Answer:

The point 'R' shows the irrational number √11 on the given number line and for better proximation using decimals, 3.2×3.2= 10.24; 3.4×3.4= 11.56

Step-by-step explanation:

It is given that we have to locate √11 on a number line, so for that we need to mark point 'O' on the number line as shown;

Now,

On the number line, point 'O' represent 0 and the point 'L' represents 3. Thus, we have OL = 3 units.

Now, we will construct LM = 1 unit, which will be perpendicular to the number line given;

=> OM = √10

Now, we will further construct MN = 1 unit, which will be perpendicular to OM;

=> ON² = OM² + MN²

=> ON = √OM² + MN²

=> √(10)² + (1)²

=> √10+1

=> √11

Furthermore, With O as the center and ON = √11 for the radius, we create an arc that crosses the number line at R resulting that line OR = √11 (radius).

Therefore, the point 'R' shows the irrational number √11 on the given number line.

For better proximation using decimals, the answers are:

3.2 × 3.2 = 10.24

3.4 × 3.4 = 11.56

<u>To know more about representation on number line, click here</u>:

brainly.com/question/13425491

#SPJ10

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Given f(x) = 5x + 7,g(x) = 3x-1 find f(g(x))
kakasveta [241]

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  3. Exponents
  4. Multiplication
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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = 5x + 7

g(x) = 3x - 1

<u>Step 2: Find</u>

  1. Substitute in functions:                                                                                    f(g(x)) = 5(3x - 1) + 7
  2. [Distributive Property] Distribute 5:                                                                 f(g(x)) = 15x - 5 + 7
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2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi
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Answer:

(a) E(X) = 950

(b) $ COV = 0.007255$

(c) P(X > 980) = 0.00001\\\\

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$ COV = \frac{\sigma}{E(X)} $

Where the standard deviation is given by

\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892

So the coefficient of variance is

$ COV = \frac{6.892}{950} $

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(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

P(X > 980)  = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980)  = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980)  = 1 - P(Z < 4.28)\\\\

The z-score corresponding to 4.28 is 0.99999

P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\

So it means that it is very unlikely that there will be more than 980 non-defective units.

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Answer:

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