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AlladinOne [14]
3 years ago
5

Solve by elimination x+y= 0 2x-y= 12​

Mathematics
2 answers:
DIA [1.3K]3 years ago
8 0

Answer:

(x,y)= (4,-4)

Step-by-step explanation:

Thanks me later

dezoksy [38]3 years ago
5 0

Answer:

m=2

Step-by-step explanation:

I calculated it sorry

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Find multiples of 30 and 40:

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40: 40, 80, 120, 160

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120/60 = 2 hours.

The bells ring together every 2 hours.

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-4.8f+6.4=-8.48 what's f 7.3y-5.18=-51.9 what's y
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3 years ago
What is 8t^5 times 8t^5?
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2 years ago
adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the
Zigmanuir [339]

Answer:

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659 and \left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

Step-by-step explanation:

The equation of the isotope decay is:

\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

\tau = \frac{5568\,years}{\ln 2}

\tau \approx 8032.926\,years

The decay time is:

t = 1315\,years + 2007\,years \pm 13\,years (There is no a year 0 in chronology).

t = 3335 \pm 13\,years

Lastly, the relative amount is estimated by direct substitution:

\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659

\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }

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4 0
2 years ago
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