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AlladinOne [14]
2 years ago
5

Solve by elimination x+y= 0 2x-y= 12​

Mathematics
2 answers:
DIA [1.3K]2 years ago
8 0

Answer:

(x,y)= (4,-4)

Step-by-step explanation:

Thanks me later

dezoksy [38]2 years ago
5 0

Answer:

m=2

Step-by-step explanation:

I calculated it sorry

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Square root of 79 rounded to the nearest hundredth?
34kurt
8.88 I think. Hope this helps :)
5 0
2 years ago
Read 2 more answers
Is my answer correct?<br> 2 1/4 + 1/4 = 2 1/2
Sholpan [36]
Perfectly correct. Two quarters do make a half :)
8 0
3 years ago
Find two positive numbers if their ratio is 8:5 and the difference is 150.
natima [27]
Let's call the two numbers x and y. We can write a system of equations to describe the situation:

5x = 8y

x - y = 150

Let's solve the first equation for x:

x = 8y/5

Now we can use substitution to solve the system by plugging 8y/5 in for x in the second equation:

(8y/5) - y = 150

Simplify:

3y/5 = 150

3y = 750

y = 250

If y = 250, then x is:

x = 8(250)/5 = 400

The answer is 250 and 400.






7 0
3 years ago
Listed below are the weights in pounds of 11 players randomly selected from the roster of the Seattle Sea-hawks when they won Su
weeeeeb [17]

Answer:

No. These measures show a thinner team of NFL players according to the mean, variance, standard deviation, and quartiles.

Step-by-step explanation:

1) The measures of variation, namely The Range, Variance, Quartiles, Interquartiles, Sum of Squares, etc. shows us how the data are dispersed.

The Range Δ is calculated:

\Delta =305-189=116 Maximum value - Minimum value for weight

Mean:

\bar{x}=\frac{189+254+235+225+190+305+202+190+252+305}{11}\approx 231.09 \:pounds

Variance:

s^{2}=\frac{\sum_{i=1}^{n} (x_i-\bar{x})^{2}}{n-1}\Rightarrow s=1923.69\\

The Standard Deviation of the sample

s=\sqrt{s^{^{2}}}\Rightarrow s\approx 43.86\\

2) Since there is no preceding exercise, the comparison was made to a recent study in which a NFL player average weight is about 245 pounds (average),

Since 25% of this list are player whose weight is 192.5 lbs and 50% (2nd Quartile) =225 lbs , finally only at the 3rd Quartile we have players above the regular NFL average with 253. This, added with the other data, allow us to say that this list is not a typical of all NFL players.

4 0
3 years ago
To show how to do this step by step
Jet001 [13]

Answer:

to do it 5 x 10 x 4 x 5 x 6 x 7 x 3 x 2 3 x 4  x5

Step-by-step explanation:

x 3x 3x 3x3 x4 x4x4 x4x  to the power  of 5 million

3 0
3 years ago
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