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Karo-lina-s [1.5K]
3 years ago
13

Really easy 6th-grade math question!

Mathematics
1 answer:
meriva3 years ago
8 0

Answer: I would say B is the right option.

Step-by-step explanation:

Adding in 0 would affect the <u>median</u>, but not by much.

<u><em>To calculate median:</em></u><em> </em>sort numbers in order from least to greatest. The middle number is the median.

<u>*Without 0:*</u>

<em />

100, 120, 130, 150   <em>Median: </em>120 and 130

<em />

<em>when there are two medians, add both numbers, then divide the sum by 2.</em>

<em />

120+130 = 250

\frac{250}{2} =125<em />

<em />

<u>*With 0:*</u>

<u></u>

0, 100, 120, 130, 150   <em>Median: </em>120

<em />

As you can see, the median does decrease from 125 to <em>120</em>. That's a <em>-5 difference.</em>

<em />

Adding in 0 would also change the <u>mean</u> because it adds another number to divide by. To calculate the mean without 0, you'd just add up 100, 120, 130, ans 150 then divide the sum by 4, <em>since there are four numbers.</em> But by adding 0 into the mix, it doesn't change the sum, but adds one more number to divide by. So instead of adding 100, 120, 130, and 150 and dividing the sum by 4, you'd divide by 5, <em>since there are now five numbers</em> because 0 was added.

<em>Lets work out the mean and see what comes up. </em>

<u>*Without 0:*</u>

100+120+130+150=500

\frac{500}{4} =125

<u>*With 0:*</u>

100+120+130+150+0=500

\frac{500}{5} =100

Here, the mean decreases from 125 to <em>100</em>. That's a <em>-20 difference!</em> Hence,<em> B is your answer.  :)</em>

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 8.4, \sigma = 1.8, n = 40, s = \frac{1.8}{\sqrt{40}} = 0.2846

Find the probability that their mean rebuild time exceeds 9.1 hours.

This is 1 subtracted by the pvalue of Z when X = 9.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{9.1 - 8.4}{0.2846}

Z = 2.46

Z = 2.46 has a pvalue of 0.9931

1 - 0.9931 = 0.0069

So the answer is B.

6 0
3 years ago
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