Itd be c.180 because itd be 12 cars each hour so times 12 by 15
Answer:
The endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).
Step-by-step explanation:
If a line connecting the midpoint of two sides and parallel to the third side of the triangle, then it is called a midsegment.
From the given figure it is noticed that the vertices of the triangle are D(1,4), E(1,1) and F(-3,3).
If the midsegment is parallel to DE, then the end points of the midsegment are mid point of DF and EF.
Midpoint formula.
![Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})](https://tex.z-dn.net/?f=Midpoint%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%29)
Midpoint of DF,
![Midpoint=(\frac{1-3}{2},\frac{4+3}{2})](https://tex.z-dn.net/?f=Midpoint%3D%28%5Cfrac%7B1-3%7D%7B2%7D%2C%5Cfrac%7B4%2B3%7D%7B2%7D%29)
![Midpoint=(-1,3.5)](https://tex.z-dn.net/?f=Midpoint%3D%28-1%2C3.5%29)
Midpoint of EF,
![Midpoint=(\frac{1-3}{2},\frac{1+3}{2})](https://tex.z-dn.net/?f=Midpoint%3D%28%5Cfrac%7B1-3%7D%7B2%7D%2C%5Cfrac%7B1%2B3%7D%7B2%7D%29)
![Midpoint=(-1,2)](https://tex.z-dn.net/?f=Midpoint%3D%28-1%2C2%29)
Therefore the endpoints of the midsegment for △DEF that is parallel to DE, are (-1,3.5) and (-1,2).
Answer:
an = 7.5 - 5.5(n - 1).
Step-by-step explanation:
The common difference d = -5.5.
The first term is given as 7.5.
Explicit formula is
an = a1 + (n - 1)d
= 7.5 + (n - 1)-5.5
= 7.5 - 5.5(n - 1)
1.) 8 to the second power which is 64 - 7
64-7=56
2.) 8(5-2) Parentheses first so 5-2=3
8x3=24
3.) 14 divided by 2= 7
4.) 5-8 divided by 4
-3 divided by 4= -0.75
Hope this helps!