We have been given that a sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. We are asked to find the difference of the volumes of the spheres.

We will use volume formula of sphere to solve our given problem.

$\text{Volume of sphere}=\frac{4}{3}\pi r^3$ , where r is radius of sphere.

The difference of volumes would be volume of larger sphere minus volume of smaller sphere.

$\text{Difference of volumes}=\frac{4}{3}\pi(\text{8 cm})^3-\frac{4}{3}\pi(\text{2 cm})^3$

$\text{Difference of volumes}=\frac{4}{3}\pi(512)\text{ cm}^3-\frac{4}{3}\pi(8)\text{ cm}^3$

$\text{Difference of volumes}=\frac{4}{3}\pi(512-8)\text{ cm}^3$

$\text{Difference of volumes}=4\pi(168)\text{ cm}^3$

$\text{Difference of volumes}=672\pi\text{ cm}^3$

Therefore, the difference between volumes of the spheres is $672\pi \text{ cm}^3$ .

3 0

3 years ago

Combine like terms to write an equivalent expression for <br><br> 2( 4y^2 + 6x - 2y^2 + 12x.)

natima [27]

8y^2 + 12x - 4y^2 + 24x
= 4y^2 + 36x

3 0

3 years ago

An art teacher buys 9 bags of cotton balls there are 68 cotton balls in each bag whitch expression is best to estimate the numbe

Phantasy [73]

Answer:

612

Step-by-step explanation:

9 x 68 = 612

8 0

3 years ago

What is the maximum number of possible extreme values for the function,

Len [333]

It is B4 so i know it is

6 0

3 years ago

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