Answer:
Width=13cm
Length=18cm
Step-by-step explanation:
Width of the Initial Photograph=9cm
Length of the Initial Photograph=14cm
If width and length are increased by an equal amount, say x
New Width=9+x
New Length=14+x
Area of the new photo is 108 square centimeters greater than the area of the original photo.
Area of Original Photo=14*9=126cm²
Aeea of the New Photo=126+108=234cm²
Therefore:
(9+x)(14+x)=234
126+9x+14x+x²-234=0
x²+23x-108=0
x²+27x-4x-108=0
x(x+27)-4(x+27)=0
(x+27)(x-4)=0
x+27=0 or x-4=0
x=-27 or x=4
Since x≠-27
x=4cm
The dimensions of the new photo are:
Width=9+x=9+4=13cm
Length=14+x=14+4=18cm
I am getting 42 Vibbezzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
This is probably in the context of a discussion of significant figures and accuracy.
When we record a measurement of 4.15 cm with two significant figures, that means we believe the exact value is in the range from 4.145 cm to 41.155 cm
Similarly 7.34 really means between 7.335 and 7.345 cm.
The minimum area rectangle is
The maximum area rectangle is
Choice A
Answer:
4x2=8
Step-by-step explanation:
This equation is simple and easy cause its base sick math
