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3 years ago

Find the slope and the equation of the line through the points (-4,9) and(8,12)

1 answer:

7 0

The formula for a slope is $\frac{y_2 - y_1}{x_2 - x_1}$ . Inserting those values into the equation, we get (12 - 9) / (8 - (-4)) = 3/12 = 1/4

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mote1985 [20]

OMGG SIS I HAVE I READY TO ILL HELP YOU :DDD

4 0

2 years ago

According to Padgett Business Services, 20% of all small-business owners say the most important advice for starting a business i

elena-s [515]

Answer:

a) There is a 6.88% probability that none of the owners would say preparing for long hours and hard work is the most important advice.

b) There is a 1.93% probability that six or more owners would say preparing for long hours and hard work is the most important advice.

c) There is a 10.32% probability that exactly five owners would say having good financing ready is the most important advice.

d) The expected number of owners who would say having a good plan is the most important advice is 2.28

Step-by-step explanation:

Questions a), b), c) are all solved as binomial distribution problems.

Question d) is a simple calculation.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For these problems

12 business owners were contacted, so $n = 12$ .

a. What is the probability that none of the owners would say preparing for long hours and hard work is the most important advice?

20% of all small-business owners say the most important advice for starting a business is to prepare for long hours and hard work, so $\pi = 0.2$ .

That is P(X=0) when $\pi = 0.2$ .

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{12,0}.(0.2)^{0}.(0.8)^{12} = 0.0688$

There is a 6.88% probability that none of the owners would say preparing for long hours and hard work is the most important advice.

b. What is the probability that six or more owners would say preparing for long hours and hard work is the most important advice?

20% of all small-business owners say the most important advice for starting a business is to prepare for long hours and hard work, so $\pi = 0.2$ .

This is:

$P = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 6) = C_{12,6}.(0.2)^{6}.(0.8)^{6} = 0.0155$

$P(X = 7) = C_{12,7}.(0.2)^{7}.(0.8)^{5} = 0.0033$

$P(X = 8) = C_{12,8}.(0.2)^{8}.(0.8)^{4} = 0.0005$

$P(X = 9) = C_{12,9}.(0.2)^{9}.(0.8)^{3} = 0.00006$

$P(X = 10) = C_{12,10}.(0.2)^{10}.(0.8)^{2} = 0.000004$

$P(X = 11) = C_{12,11}.(0.2)^{11}.(0.8)^{1} = 0.0000002$

$P(X = 12) = C_{12,12}.(0.2)^{12}.(0.8)^{0} = 0.000000004$

So:

$P = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.0155 + 0.0033 + 0.0005 + 0.000006 + 0.000004 + 0.0000002 + 0.000000004 = 0.0193$

There is a 1.93% probability that six or more owners would say preparing for long hours and hard work is the most important advice.

c. What is the probability that exactly five owners would say having good financing ready is the most important advice?

Twenty-five percent say the most important advice is to have good financing ready, so $\pi = 0.25$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 5) = C_{12,5}.(0.25)^{5}.(0.75)^{7} = 0.1032$

There is a 10.32% probability that exactly five owners would say having good financing ready is the most important advice.

d. What is the expected number of owners who would say having a good plan is the most important advice?

Nineteen percent say having a good plan is the most important advice, so that is $0.19*12 = 2.28$

The expected number of owners who would say having a good plan is the most important advice is 2.28

4 0

3 years ago

Jada Elena and Lin walked a total of 37 miles last week. jada walked 4 more miles that elena, and Lin walked 2 more miles than j

MA_775_DIABLO [31]

Answer:

Jada walked $13\ miles$

Elena walked $9\ miles$

Lin walked $15\ miles$

Step-by-step explanation:

Let

x----> total miles walked by Jada

y----> total miles walked by Elena

z----> total miles walked by Lin

we know that

$x+y+z=37$ -----> equation A

$x=y+4$ -----> $y=x-4$ ------> equation B

$z=x+2$ ------> equation C

Substitute equation C and equation B in equation A and solve for x

$x+(x-4)+(x+2)=37$

$3x=37+2$

$3x=39$

$x=13\ mi$

Find the value of y

$y=13-4=9\ mi$

Find the value of z

$z=13+2=15\ mi$

therefore

Jada walked $13\ miles$

Elena walked $9\ miles$

Lin walked $15\ miles$

3 0

3 years ago

Suppose a club publishes a newsletter. Expenses are$.50 for printing and mailing each copy, plus$300 total for research and writ

luda_lava [24]

200 copies must be sold

n= number od newsletters

0,50*n+300=2,00*n

300=1,5*n

Divide both sides by 1,5

200=n

0,50*200+300=2*200

100+300=400

400=400

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3 years ago

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You suspect that the spiciness of food served in a restaurant is positively correlated with number of soft drinks ordered. What

Naily [24]

<span>B) Observe several cases of people ordering food of varying spice-levels and number of soft drinks ordered. thats what i think though.</span>

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3 years ago

Read 2 more answers