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3 years ago

The midpoint of the segment joining points (cd) and (m,n) is

Mathematics

1 answer:

lana [24]3 years ago

6 0

yxhfufugugufye6e633648tudydyjeyetshxhchxhd

Step-by-step explanation:

yxhfufugugufye6e633648tudydyje

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In a quadrilateral ABCD, AO and BO are bisectors of angle A and angle B respectively

worty [1.4K]

Answer: ABCD is a quadrilateral

To prove : ∠AOB=

(∠C+∠D)

AO and BO is bisector of A and B

∠1=∠2∠3=∠4...(1)

∠A+∠B+∠C+∠D=360

(Angle sum property)

(∠A+∠B+∠C+∠D)=180...(2)

In △AOB

∠1+∠3+∠5=

(∠A+∠B+∠C+∠D)

∠1+∠3+∠5=∠1+∠3+

(∠C+∠D)

∠AOB=

(∠C+∠D)

Explanation: In a quadrilateral ABCD. AO and BO are bisectors of angle A and angle B respectively. Prove that ∠AOB=

{∠C+∠D}.

3 0

3 years ago

Noah and Lin are making paper cones to hold popcorn to hand out at parent math night. They want the cones to hold 9 cubic inches

DanielleElmas [232]

Answer:

So, The possible values of h and r are

1. r = 3 , h = 3

2. r = 1, h = 27

3. r = 2, h = 6.75

Step-by-step explanation:

P.S - The exact ques is -

As we know that Volume of cone , V = $\frac{1}{3}\pi r^{2}h$

As given,

V = $9\pi$

⇒ $\frac{1}{3}\pi r^{2}h = 9\pi \\ \frac{1}{3} r^{2}h = 9 \\r^{2}h = 27$

So,

The possible values of h and r are

1. r = 3 , h = 3

2. r = 1, h = 27

3. r = 2, h = 6.75

In Case I-

When r = 3, h = 3

(3)² ×3 = 9×3 = 27

Satisfied

Case II-

r = 1, h = 27

(1)²×27 = 1×27 = 27

Satisfied

Case III-

r = 2, h = 6.75

(2)²×6.75 = 4×6.75 = 27

Satisfied

8 0

3 years ago

How many one-to-one correspondences are there between two sets with<br><br> 6 elements each?

WINSTONCH [101]

Answer:

6 * 5 * 4 * 3 * 2 * 1, i.e. 6! or 720. Of course, since both sets have the same number of elements, you can't have one-to-one without being onto, aka a surjection, so “one to one correspondence” is the right term (or bijection—merci, M.

Hope it helps >3!

3 0

3 years ago

Read 2 more answers

-5n+8= -7 in two-step equations-integers

Paha777 [63]

Answer:

n=3

Step-by-step explanation:

So the question we are to solve is to be solved by collecting like terms and by division

So let's solve the question

-5n+8=-7

So let's solve

-5n+8=-7

Substrate 8 from both sides

-5n=-15

So let's make n the subject of formula by dividing both sides by -5

n=3

Therefore the final answer for the given question is 3

3 0

3 years ago

Simplify expressions

charle [14.2K]

<h3>a) $\frac{2}{5} \div ( - \frac{3}{4} )$ </h3><h3>■Dividing a positive and a negative equals a negative: (+)÷(-)=(-)</h3>

<h2> $- \frac{2}{5} \div \frac{3}{4}$ </h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2> $- \frac{2}{5} \times \frac{4}{3}$ </h2><h3>■Multiply the fractions</h3>

<h3>Hence, Quotient = $- \frac{8}{15}$ </h3>

<h3>b) $0.4 \div ( - 0.75)$ </h3><h3>■Convert the decimals into a fractions</h3>

<h2> $\frac{2}{5} \div ( - \frac{3}{4} )$ </h2><h3>■Dividing a positive and a negative equals a negative: (+)÷(-)=(-)</h3>

<h2> $- \frac{2}{5} \div \frac{3}{4}$ </h2><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2> $- \frac{2}{5} \times \frac{4}{3}$ </h2><h3>■Multiply the fractions</h3>

<h2> $- \frac{8}{15}$ </h2><h3>Hence, Quotient is $- \frac{8}{15}$ </h3>

<h3>c) $- \frac{2}{5} \div \frac{3}{4}$ </h3><h3>■To divide by a fraction, multiply by the reciprocal of that fraction</h3>

<h2> $- \frac{2}{5} \times \frac{4}{3}$ </h2><h3>■Multiply the fractions</h3>

<h2> $- \frac{8}{15}$ </h2><h3>Hence, The Quotient is $- \frac{8}{15}$ </h3>

4 0

2 years ago