6y + 12 = 3y - 3
Subtract 3y on both sides
3y + 12 = -3
Subtract 12 on both sides
3y = -15
Divide by 3 on both sides
y = -5
Observe the graph below. This graph represents the scenario.
The question is ill formated, the complete question is
In a simulation, a moving object accelerates from rest to 4 meters per second in 2 seconds. For the following three seconds, it increases linearly until it reaches a speed of 10 meters per second. Following three seconds at that speed (acceleration = 0), the item progressively decelerates until it comes to rest two seconds later. Draw the graph of this scenario for 10 seconds?
I'll describe how the graph may show.
It will move diagonally upward from time 0 to 2 seconds until it reaches the y axis at a speed of 4 m/s.
Then, from 2 to 5, the position will move up diagonally until it reaches the y axis at a speed of 10 m/s.
The next 5 to 8 seconds will be horizontal.
After that, it will descend diagonally.
Observe the graph below. This graph represents the scenario.
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Answer:
Not Determinable
Step-by-step explanation:
Simplifying
Ln(4x + 1) = 6
Reorder the terms:
nL(1 + 4x) = 6
(1 * nL + 4x * nL) = 6
(1nL + 4nxL) = 6
Solving
1nL + 4nxL = 6
Solving for variable 'n'.
Move all terms containing n to the left, all other terms to the right.
Reorder the terms:
-6 + 1nL + 4nxL = 6 + -6
Combine like terms: 6 + -6 = 0
-6 + 1nL + 4nxL = 0
The solution to this equation could not be determined.
Answer:
A
Step-by-step explanation: