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OverLord2011 [107]
3 years ago
13

In the picture above, parallel lines p and q are cut by transversal line t. If the measure of angle 4 is 43 degrees, then the me

asure of angle 6 is 43 degrees and the measure of angle 5 is ______ degrees. The measure of angle 8 is 43 degrees and the measure of angle 1 is _____ degrees.

Mathematics
1 answer:
pshichka [43]3 years ago
6 0

Answer:

angle 5 is <u>137</u> degrees

angle 1 is <u>137</u> degrees

Step-by-step explanation:

angle 5 and 6 are supplementary angles meaning together they add up to 180 degrees. to find angle 5 you must find the difference:

180-43=137

so angle 5 is 137 degrees.

likewise, angle 1 and angle 4 are supplementary angles. find the difference:

180-43=137

so angle 1 is also 137 degrees.

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How do you solve this ?
saveliy_v [14]

When given a value of the variable, we replace each instance of the variable in the problem with that number. In this case, the expression becomes:


\frac{3^2 + 3}{3 - 1}


After this, we merely need to simplify the answer.


\frac{9 + 3}{3 - 1}


\frac{12}{2}


Simplifying 12/2 gives us the answer 6.

5 0
3 years ago
Help me solve,Brainlist for first to answer
Vanyuwa [196]

Answer:

(i) the other two sides are 6 and  6\sqrt{2}

(ii) the other two sides are   \frac{4}{3} and                                         \frac{8}{3}

Step-by-step explanation:

(i)  Sine: sin(θ) = Opposite ÷ Hypotenuse

    Cosine: cos(θ) = Adjacent  ÷ Hypotenuse

    Tangent: tan(θ) = Opposite ÷ Adjacent

Here adjacent side = 6

opposite side = d

angle = 45°

other angles are 90° and 45°

tan (45) = Opposite ÷ Adjacent

 1 = d ÷ 6

∴ d = 6 × 1 = 6

so opposite side = 6

Hypotenuse ² = opposite side ² + adjacent side²

                      =  6² + 6²

                      = 36 + 36

                       = 72

hypotenuse = \sqrt{72}

                     = 6\sqrt{2}

the other two sides are 6 and  6\sqrt{2}

(ii) here adjacent side = 4√3

angle = 30°

other angles are 90° and 60°

opposite side = d

tan ( 30) = opposite ÷ adjacent

 \frac{1}{\sqrt{3}} = d ÷ 4√3

\frac{1}{\sqrt{3}} = d × (\frac{\sqrt{3}}{4})

                       3 d = 4

therefore d = \frac{4}{3}

therefore opposite side = \frac{4}{3}

Hypotenuse ² = opposite side ² + adjacent side²

                        =( \frac{4}{3})² +( \frac{4}{\sqrt{3}})²

                        = \frac{64}{9}

therefore hypotenuse = \sqrt{\frac{64}{9}}

                                     =\frac{8}{3}

the other two sides are   \frac{4}{3} and                                    \frac{8}{3}

7 0
4 years ago
Dale currently has $599 in his savings account. Prior to getting paid, he had $230 in his savings account. How much was Dale’s p
OleMash [197]
$599.00 - $230.00 = $369.00
8 0
4 years ago
Read 2 more answers
Mr. Champion invests 34,000 into a money-market fund that pays 4.8% simple interest. How long will it take for him to earn $8,16
Tanzania [10]

Answer:

5 years

Step-by-step explanation:

Step one:

Given Information

Principal= $34,000

rate = 4.8%

SImple interest = $8,160

Required

The time T of the investment

Step two:

the expression for simple interest is

SI= PRT/100

substitute

8160 = 34000*4.8*T/100

cross multiply we have

8160*100= 34000*4.8*T\\\\816000= 163200T\\\\

divide both sides by 163200

816000/163200= T\\\\T= 5 years

4 0
3 years ago
Simplify 16 - 12 ÷ 4 +3 (6-2) show working plz ​
ira [324]

Answer:

20

Step-by-step explanation:

16-12/4+3(6-2)      subtract 6 and 2

16-12/4+3+4          divide 12 and 4

16-3+3+4              subtract 16 and 3

13+3+4                 add all 3 numbers

13+7

20

4 0
3 years ago
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