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tekilochka [14]
3 years ago
6

Which of the following is true about file formats?

Computers and Technology
2 answers:
MA_775_DIABLO [31]3 years ago
7 0
It’s lil uzi Fer debí Moo cosmo I
234
Me
Aloiza [94]3 years ago
3 0

Answer:

i feel like the answer to this question would be ''Free file formats may be either open or closed.'' If  i'm wrong, plz let me know ^^

Explanation:

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While reading difficult content, you should always start witha.Surveying the chapterc.Reading the chapterb.Defining vocabulary w
katrin [286]
When reading difficult content you should- Survey the chapter.

Surveying the chapter allows you to better interpret the literary text and therefore be able to answer the following questions or summarize. 

Hope I helped,
-CSX :)
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3 years ago
Which of the following best describes the purpose of a design specification?
snow_lady [41]

Answer:

it is.    Describing the requirements for how a program will work or users will interact with it

Explanation:

mark brainlist

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To use   ( 2 complement ) answer it (101101)2 – (1100)2 =   (                    )2
Tju [1.3M]

Answer:

2(101101) - 2(1100) = 200002

Explanation:

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5 0
3 years ago
File Sales.java contains a Java program that prompts for and reads in the sales for each of 5 salespeople in a company. It then
myrzilka [38]

Answer:

import java.util.Scanner;

public class Sales

{

public static void main(String[] args) {

   

    int sum;

    Scanner input = new Scanner(System.in);

   

    System.out.print("Enter number of salespeople: ");

    int salespeople = input.nextInt();

    int[] sales = new int[salespeople];

       

    for (int i=0; i<sales.length; i++)

    {

     System.out.print("Enter sales for salesperson " + (i+1) + ": ");

     sales[i] = input.nextInt();

    }

    System.out.println("\nSalesperson   Sales");

    System.out.println("--------------------");

    sum = 0;

       int maxSale = sales[0];

       int minSale  = sales[0];

       int minId=1;

       int maxId=1;

    for (int i=0; i<sales.length; i++)

    {

               System.out.println("     " + (i+1) + "         " + sales[i]);

 sum += sales[i];

  if(maxSale < sales[i])

           {

               maxSale = sales[i];

               maxId = i+1;

           }

           if(minSale > sales[i])

           {

               minSale = sales[i];

               minId = i+1;

           }

   }

System.out.println("Total sales: " + sum);

       System.out.println("The average sale is: " + sum / salespeople );

       System.out.println("Salesperson "+ maxId + " had the highest sale with "+ maxSale + ".");

       System.out.println("Salesperson "+ minId + " had the lowest sale with "+ minSale + ".");

       

       int amount = 0;

       int counter = 0;

       System.out.print("Enter an amount: ");

       amount = input.nextInt();

       for (int i=0; i<sales.length; i++)

    {

     if(sales[i] > amount) {

         counter++;

         System.out.println("Salesperson "+ (i+1) + " exceeded given amount. (Number of sales: " + sales[i] +")");

     }

    }

       System.out.println("Number of salespeople exceeded given amount is: "+ counter);

}

}

Explanation:

- Ask the user for the number of salesperson

- According to entered number, create an array called sales to hold sale number for each person

- In the first for loop, assign the given sales numbers

-  In the second for loop, print all the sales people with sales, calculate the total sales. Also, find the minimum and maximum sales numbers with associated individuals.

- Print total, average, highest, and lowest sales.

- Ask user enter an amount

- In the third for loop, find the sales people who exceeded this amount.

- Print number of sales people who exceeded the amount.

8 0
3 years ago
I AM GIVING BRAINLEST!!!!!!!!
elena-s [515]

Answer:

B. 10%

Explanation:

The JPG file is a great format as it often manages to compress files to 1/10 of the size of the original file which is especially good for saving on bandwidth. JPG is a popular graphic format, which is characterized by a high degree of compression, which leads to a decrease in image quality.

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