Answer:
○ 
Explanation:
Accourding to one of the circle equations, 
the centre of the circle is represented by 
Moreover, all negative symbols give you the OPPOCITE TERMS OF WHAT THEY <em>REALLY</em> ARE, so you must pay cloce attention to which term gets which symbol. Another thing you need to know is that the radius will ALWAYS be squared, so no matter how your equation comes about, make sure that the radius is squared. Now, in case you did not know how to define the radius, you can choose between either method:
Pythagorean Theorem
Sinse we are dealing with <em>length</em>, we only desire the NON-NEGATIVE root.
Distanse Equation
![\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = d \\ \\ \sqrt{[-7 + 4]^2 + [-2 - 2]^2} = r \hookrightarrow \sqrt{[-3]^2 + [-4]^2} = r \hookrightarrow \sqrt{9 + 16} = r; \sqrt{25} = r \\ \\ \boxed{5 = r}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Csqrt%7B%5B-x_1%20%2B%20x_2%5D%5E2%20%2B%20%5B-y_1%20%2B%20y_2%5D%5E2%7D%20%3D%20d%20%5C%5C%20%5C%5C%20%5Csqrt%7B%5B-7%20%2B%204%5D%5E2%20%2B%20%5B-2%20-%202%5D%5E2%7D%20%3D%20r%20%5Chookrightarrow%20%5Csqrt%7B%5B-3%5D%5E2%20%2B%20%5B-4%5D%5E2%7D%20%3D%20r%20%5Chookrightarrow%20%5Csqrt%7B9%20%2B%2016%7D%20%3D%20r%3B%20%5Csqrt%7B25%7D%20%3D%20r%20%5C%5C%20%5C%5C%20%5Cboxed%7B5%20%3D%20r%7D)
Sinse we are dealing with <em>distanse</em>, we only desire the NON-NEGATIVE root.
I am joyous to assist you at any time.
Sine 61 = RS / hypotenuse
RS = Sine 61 * hypotenuse
RS = 0.87462 * 8
RS =
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6.99696
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Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Answer:
So the solution would be (1,-2). Remember you can always validate that the solution is correct by plugging it into both equations. But this is the same as the first equation, y=3x-5. Since they are the SAME line they will have infinite solutions.
Step-by-step explanation:
