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lbvjy [14]
3 years ago
6

Light refracts when:

Physics
1 answer:
VashaNatasha [74]3 years ago
6 0

Answer:

the answer of the question is B

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PLEASE HELP QUICKLY!!!!!
Grace [21]

Answer:

D air

Explanation:

it is not found on the periodic table

brainliest plsssssssssssssssss

3 0
3 years ago
What is the mass of a baseball that has a kinetic energy of 105 J and is traveling at 10 m/s?​
kkurt [141]

Answer:

\boxed {\boxed {\sf 2.1 \ kilograms}}

Explanation:

Kinetic energy is the energy an object possesses due to motion. The formula 1/2 the product of mass and the squared velocity.

E_k=\frac{1}{2} mv^2

We know the baseball's kinetic energy is 105 Joules. It is also traveling at a velocity of 10 meters per second. `

First, convert the units of Joules to make unit cancellation easier later in the problem. 1 Joule (J) is equal to 1 kilogram square meter per square second (kg*m²/s²). The baseball's kinetic energy of 105 J is equal to 105 kg*m²/s².

Now we know 2 values:

  • E_k= 105 \ kg*m^2/s^2
  • v= 10 \ m/s

Substitute these values into the formula.

105 \ kg*m^2/s^2= \frac{1}{2} m (10 \ m/s)^2

Now we need to solve for m, the mass. Solve the exponent.

  • (10 m/s)²= 10 m/s * 10 m/s = 100 m²/s²

105 \ kg *m^2/s^2 = \frac{1}{2} m (100 \ m^2/s^2)

Multiply on the right side.

105 \ kg *m^2/s^2 =  m (\frac{1}{2} * 100 \ m^2/s^2)

105 \ kg *m^2/s^2 =  m (50 \ m^2/s^2)

The variable, m, is being multiplied by 50 square meters per square second. The opposite of multiplication is division, so we divide both sides by that value.

\frac {105 \ kg *m^2/s^2 }{50 \ m^2/s^2}=  \frac{ m (50 \ m^2/s^2)}{50 \ m^2/s^2}

\frac {105 \ kg *m^2/s^2 }{50 \ m^2/s^2}= m

The units of square meter per square second will cancel out.

\frac {105 }{50} \ kg= m

2.1 \ kg=m

The mass of the baseball is <u>2.1 kilograms. </u>

5 0
3 years ago
What is the energy of an object in motion
tensa zangetsu [6.8K]
The answer is kinetic energy

5 0
3 years ago
Read 2 more answers
You should be extremely careful when handling a soldering iron. This is owing to the dangerous temperatures that can be reached
Bogdan [553]
I believe this is true
3 0
3 years ago
An elastic conducting material is stretched into a circular loop of 14.7 cm radius. It is placed with its plane perpendicular to
Hunter-Best [27]

Answer: 0.66 V

Explanation:

Given

Magnetic field, B = 0.963 T

Instantaneous rare = 74.5 cm/s = 0.745 m/s

radius, r = 14.7 cm = 0.147 m

We will use the formula

emf = dΦ/dt

emf = d(BA)/dt

emf = d(Bπr²)/dt

if B is constant, then we can say

emf = Bπ d(r²)/dt on differentiating, we have,

emf = Bπ (2r dr/dt)

emf = 2πrB dr/dt substituting each values, we have

emf = 2 * 3.142 * 0.147 * 0.963 * 0.745

emf = 0.66 V

Therefore, the induced emf in the loop at that instant is 0.66 V

3 0
3 years ago
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