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STatiana [176]
3 years ago
15

Lucy boards a crowded bus as it sits in the station. There are no available seats, so Lucy stands in the center aisle next to a

support pole. As the bus starts moving forward and picks up speed, Lucy holds the pole tightly to avoid falling over backward. While the bus is speeding up, what is the direction of the total force (if any) on Lucy?a. Is it forward b. Baclwards c. The total force is zero?
Physics
1 answer:
GenaCL600 [577]3 years ago
5 0

The acceleration of the bus is forward, and said acceleration is transmitted directly to Lucy, so the direction of the Force (We gather that force is equal to mass by acceleration) will be forward as well. Lucy's immediate action will be to fall back because she tries to resist this movement.

Therefore the correct answer is A.

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A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².

A shopper is pushing a cart down a grocery store aisle. The movement of the cart is:

  • It starts from rest.
  • From t = 0 s to t = 4.0 s it is accelerated with a constant force.
  • From t = 4 s to t = 8.0 s it receives just enough force to balance the friction on the cart.
  • From t = 8 s to t = 12 s it is decelerated until it comes to rest.

All in all, at the initial time (t = 0 s), the velocity is 0 m/s (rest) and at the final time (t = 12 s) the velocity is 0 m/s as well (rest). The average acceleration in that period is:

a = \frac{v_{12}-v__o}{t_{12}-t_0} = \frac{0m/m-0m/s}{12s-0s}  = 0 m/s^{2}

A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².

Learn more: brainly.com/question/16274121

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3 years ago
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Answer:

The voltage will quadruple

Explanation:

The power dissipated in a circuit is given by

P=\frac{V^2}{R}

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V is the voltage

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In this problem, the voltage across the circuit is doubled:

V' = 2V

So the new power dissipated is

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