Radial acceleration is given by

where

then

Now

Using the relation


Putting into rpm
I ueueeieueueuekdududieisidudud
Answer:
Being a plane mirror the Image is formed 3 metres beyond the mirror . So total distance is 3+3 = 6metres
Answer:
-1 m/s
Explanation:
From the law of conservation of linear momentum, the sum of initial and final momentum should be equal. Momentum, p is expressed as the product of mass and velocity. Therefore, p=mv where m and v represent mass and velocity respectively. In this case

Where subscripts d and u represent downwards and upwards respectively while c is common hence common velocity which is unknown in this case. Taking downwards as negative while upwards as positive then substituting -3 m/s for downward speed while 3 m/s for upward speed, the masses as given then
(2*-3)+(1*3)=(2+1)v
V=-1 m/s hence downward direction
Explanation:
Let omega = angular velocity (in rad/s). Then
omega = (# of oscillations)/(6 s)
= (30 osc)/(6 s) = 5 osc/s
We need to convert this to rad/s:
omega = (5 osc/s)(2π rad/osc)
= 10π rad/s
= 31.4 rad/s