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Nutka1998 [239]
2 years ago
10

Fill in the missing value in each equation:a)0.25+_____=0b)-5×_____=-5c)_____×-6=0

Mathematics
1 answer:
Mashutka [201]2 years ago
8 0

Answer:

a) -0.25

b) 1

c)0

Step-by-step explanation:

a) 0.25 + (-0.25)=0

b) -5*1=-5

c) 0*(-6)=0

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Answer:

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Step-by-step explanation:

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3 years ago
The following observations are on stopping distance (ft) of a particular truck at 20 mph under specified experi- mental conditio
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Answer:

see explaination

Step-by-step explanation:

Data : 32.1 , 30.6 , 31.4 , 30.4 , 31.0 , 31.9

Mean X-bar = 31.23

SD = 0.689

a)

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Alternate Hypothesis : Xbar > mu

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= (31.23 - 30 ) /(0.689/sqrt(6))

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The data suggest that true average stopping ditance exceeds the maximum.

b)

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ii) SD = 0.65

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= (31.23 - 32) /(0.65/sqrt(6))

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c)

i) SD = 0.8

mu = 31

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 31) /(0.8/sqrt(6))

= 0.704

P-value = 0.4814 Answer

ii) SD = 0.8

mu = 32

z = (Xbar - mu) / (SD/sqrt(n))

= (31.23 - 32) /(0.8/sqrt(6))

= -2.357

P-value = 0.0184 Answer

The probabilities obtained in part c are comparatively higher than that of part b.

d)

i) For alpha =0.01

z = (Xbar - mu) / (SD/sqrt(n))

=> -2.32 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-2.32

=> sqrt(n) = (0.65*(-2.32)) / (31.23 - 31)

=> n = 43 Answer

ii) For beta =0.10

z = (Xbar - mu) / (SD/sqrt(n))

=> -1.28 = (31.23 - 31) /(0.65/sqrt(n))

=> (0.65/sqrt(n)) = (31.23 - 31)/-1.28

=> sqrt(n) = (0.65*(-1.28)) / (31.23 - 31)

=> n = 13 Answer

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2 years ago
Three-fifths of the sum of 9 and f
blsea [12.9K]

Answer:  \frac{3}{5} f+\frac{27}{5}

Step-by-step explanation:

Three-fifths of the sum of 9 and f is \frac{3}{5} (9+f)=\frac{27}{5} +\frac{3}{5} f=\frac{3}{5} f+\frac{27}{5}

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Answer:

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Step-by-step explanation:

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