Let's simplify step-by-step.<span><span><span><span>1+<span>8n</span></span>+<span>4n</span></span>+1</span>−<span>2n</span></span><span>=<span><span><span><span><span>1+<span>8n</span></span>+<span>4n</span></span>+1</span>+</span>−<span>2n</span></span></span>Combine Like Terms:<span>=<span><span><span><span>1+<span>8n</span></span>+<span>4n</span></span>+1</span>+<span>−<span>2n</span></span></span></span><span>=<span><span>(<span><span><span>8n</span>+<span>4n</span></span>+<span>−<span>2n</span></span></span>)</span>+<span>(<span>1+1</span>)</span></span></span><span>=<span><span>10n</span>+2
</span></span>Answer:<span>=<span><span>10n</span>+<span>2</span></span></span>
F(x) = x² - 13x + 30
f(x) = x² - 3x - 10x + 30 = 0
f(x) = x(x - 3) -10(x - 3) = 0
f(x) = (x-3)(x-10) = 0
f(x) = 3 OR 10
In short, Your Answer would be Option B & D
Hope this helps!
The leg would be the hypotenuse of the triangle on the ends of the trapezoid. The top base is 5 and bottom 11, the difference is 6 inches. This gives 3 inches on each side with a height of 4.
Use Pythagorean theorem to find the hypotenuse. 3^2+4*2=c^2
9+16=c^2
25=c^2
5.=c
The leg is 5 in
Yes! Because 8x5 is 40. So there would be more than enough for each student!
