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2 years ago

I WILL GIVE BRAINLIEST PLZZZ HELP AND NO LINKS!!!

Mathematics

2 answers:

Hatshy [7]2 years ago

5 0

Answer:

The answer is C

Step-by-step explanation:

kirill [66]2 years ago

4 0

Answer:

C.) 7, 8, 9, 1, 3, 7, 2, 4

Step-by-step explanation:

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3/4 x 3 2/5 - 5/5(find the value of each of the following)

Triss [41]

The value of the given expression is $\frac{-13}{20}.$

Solution:

Given expression is $\frac{3}{4} \times3\frac{2}{5}-\frac{5}{5}$ .

Let us first convert mixed fraction into improper fraction.

$3\frac{2}{5}=\frac{(3\times5)+2}{5}=\frac{17}{5}$

Substitute this in the given expression.

$\frac{3}{4} \times3\frac{2}{5}-\frac{5}{5}=\frac{3}{4} \times\frac{7}{15}-\frac{5}{5}$

$=\frac{21}{60}-\frac{5}{5}$

To simplify the above expression, 21 and 60 are cancelled by 3.

$=\frac{7}{20}-\frac{1}{1}$

Do cross multiplication to make the denominator same.

$=\frac{7}{20}-\frac{20}{20}$

$=\frac{7-20}{20}$

$=\frac{-13}{20}$

The value of the given expression is $\frac{-13}{20}.$

7 0

2 years ago

( PLEASE HELP, WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT !! )

kolezko [41]

Answer:

D) 4,6,7

Step-by-step explanation:

U 2 can help me by marking as brainliest.........

3 0

2 years ago

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3/4 (4y+8)= 5+3y solve for y: please help

4vir4ik [10]

Answer:

No Soultion

Step-by-step explanation:

7 0

3 years ago

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Find The Value of X: A= 12 B= 16 C= 21 D= 24

Dmitriy789 [7]

Answer:

x = 21

Step-by-step explanation:

The 2 angles form a straight angle and are supplementary, thus

7x + 9 + 2x - 18 = 180, that is

9x - 9 = 180 ( add 9 to both sides )

9x = 189 ( divide both sides by 9 )

x = 21

5 0

3 years ago

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Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago