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ki77a [65]
2 years ago
12

Which are the solutions of x² = 19x + 12​

Mathematics
1 answer:
Sever21 [200]2 years ago
4 0

Answer:

\{x=\frac{19-\sqrt{409} }{2}\ , \  x=\frac{19+\sqrt{409} }{2}\}

Step-by-step explanation:

x² = 19x + 12

⇔ x² - 19x - 12 = 0

Calculating the discriminant :

b² - 4ac = (-19)² - 4×1×(-12) = 409

The discriminant is positive ,then the equation has two solutions.

x=\frac{19-\sqrt{409} }{2} \ \ or\ \ x=\frac{19+\sqrt{409} }{2}

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