Answer:
a = 32
Step-by-step explanation:
This is a right triangle and the square value of hypotenuse is equal to sum of square value of other two side lengths
68^2 = 60^2 + a^2
4624 = 3600 + a^2
4624 - 3600 = a^2
1024 = a^2 find the root for both sides
32 = a
Answer:
et's solve for x.
5y−4x=−72y+4z
Step 1: Add -5y to both sides.
−4x+5y+−5y=−72y+4z+−5y
−4x=−77y+4z
Step 2: Divide both sides by -4.
−4x
−4
=
−77y+4z
−4
x=
77
4
y−z
Answer:
x=
77
4
y−z
Let's solve for y.
5y−4x=−72y+4z
Step 1: Add 72y to both sides.
−4x+5y+72y=−72y+4z+72y
−4x+77y=4z
Step 2: Add 4x to both sides.
−4x+77y+4x=4z+4x
77y=4x+4z
Step 3: Divide both sides by 77.
77y
77
=
4x+4z
77
y=
4
77
x+
4
77
z
Answer:
y=
4
77
x+
4
77
z
Step-by-step explanation:
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Alright.
For 7, you'll want to put congruent sides equal to each other, assuming they are parallelograms. So, you'll get the two equations:
3x+2=23
2y-7=9
Solve using GEMDAS/PEMDAS, and you'll get these answers.
3x+2=23
3x=21
x=7
2y-7=9
2y=2
y=1
For 8, you'll want to do the exact same thing, formatting the numbers to equal each other. You'll get these two equations:
3y+5=14
2x-5=17
Solving them would make:
3y+5=14
3y=9
y=3
2x-5=17
2x=22
x=11
For 9, you have to remember that the angle opposite of one angle in a defined parallelogram are congruent. Thus:
130=2h
5k=50
solve them and you get
h=65
k=10
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Hope that helped. Good luck.
