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Butoxors [25]
3 years ago
14

On the coordinate plane below, quadrilaterals TRAP and HELP are similar to each other.

Mathematics
1 answer:
Elanso [62]3 years ago
6 0

Answer:Quadrilateral TRAP has an area that is one-fourth the area of quadrilateral HELP.

Step-by-step explanation: Because you rearrange the squares and it is 1/4

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Which expressions are equivalent to 3g+6(-g+(-5))?
s2008m [1.1K]

c) None of the above.

When 3g+6(-g+(-5)) is broken down, it makes -3g+-5, but I don't know, I'm not confident with my answer and I'm probably wrong.

7 0
3 years ago
Read 2 more answers
Simplify the following expression. 6^1/3 divided 6^10/3<br> (with picture)
Juli2301 [7.4K]

Answer:

<u>The correct answer is A. 1/216</u>

Step-by-step explanation:

Let's simplify the expression:

6^1/3 divided 6^10/3

6^1/3 = ∛ 6 and 6^10/3 = ∛ 6¹⁰, therefore:

∛ 6 / ∛ 6¹⁰

∛ 6 * 1/∛ 6¹⁰ (Flipping the reciprocal)

∛ 6 * 1/(∛ 6 * ∛ 6⁹)

1/∛ 6⁹ (Cancelling down ∛ 6 in the numerator and denominator)

1/6³ = 1/6 * 6 * 6 = 1/216

<u>The correct answer is A. 1/216</u>

5 0
3 years ago
IMMEDIATE HELP PLS THANKS &lt;33
Ksenya-84 [330]
Reflect across the y axis and moved through the translation x = 2
3 0
4 years ago
How many seasons old is Darla if she is 24 years old?​
Natalija [7]
She would be 6 seasons old since there are 4 seasons in a year
6•4=24
I believe that would be the answer
5 0
4 years ago
Read 2 more answers
Please help me on this!
denis23 [38]

Answer:

The Proof is given below.

Step-by-step explanation:

Given:

P is the center of Circle

∠ONE ≅ ∠TEN

To Prove:

∠5 ≅ ∠6

Proof:

Exterior Angle Theorem:

Exterior Angle Property of a Triangle states that measure of exterior angle of a triangle is equals to the sum of measures of its interior opposite angles.

STATEMENT                                                   REASON

1. So In ΔONE,

\angle 5=\angle ONE+\angle 2     1. Exterior Angle Property of a Triangle.

2. Similarly In ΔTEN,

\angle 6=\angle TEN+\angle 1      2. Exterior Angle Property of a Triangle.

3. But , ∠ONE ≅ ∠TEN                                 3. Given

4. And P is the center of circle So

PN=PE                                             4.radius of same circle

5. ΔPEN is an Isosceles triangle,

∴ ∠ 1 ≅ ∠ 2                                                     5. Isosceles triangle property

6. ∴ ∠5 ≅ ∠6                                                  6. From 3 and 5 Transitive Property.........Proved

5 0
3 years ago
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