Answer:
The proportion of people who were caught after being on the 1010 Most Wanted list would be 40.81%.
Step-by-step explanation:
Since the FBI wants to determine the effectiveness of their 1010 Most Wanted list, and to do so, they need to find out the fraction of people who appear on the list that are actually caught, supposing a sample of 517517 suspected criminals is drawn, and of these people, 211211 were captured, to estimate the proportion of people who were caught after being on the 1010 Most Wanted list using this data, the following calculation must be performed:
517,517 = 100
211,211 = X
211,211 x 100 / 517,517 = X
21,121,100 / 517,517 = X
40.81 = X
Therefore, the proportion of people who were caught after being on the 1010 Most Wanted list would be 40.81%.
Answer:
18 plastic propellers, 18 Bug Antenna, 24 moose antlers,
Step-by-step explanation:
When we multiply our total sum of 60 by certain decimal values by converting the factions to decimals we can get each type of hats count.
1/3 works out to be 0.30
60×0.3 = 18
2/5 works out to be 0.40
60×0.4 = 24
To find out the remaining amount that is plastic propellers you subtract the added hats and the total value.
60 - (18 + 24)
60 - 42
18
Answer:
R V
1 9π in³
2 36π in³
3 81π in³
Step-by-step explanation:
For, r = 1
V = π(1)²9 = 9π in³
For, r = 2
V = π(2)²9 = 4*9π in³ = 36π in³
For r = 3
V = π(3)²9 = 9*9π in³ = 81π in
R V
1 9π in³
2 36π in³
3 81π in³
Answer:
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Step-by-step explanation:
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Answer to the question is: I
