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2 years ago

What is the approximate circumstances of the circle shown below?

Mathematics

1 answer:

dangina [55]2 years ago

5 0

Answer:

the answer to this is D) 61.2

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Could you give me the reason please ?ASAP thank you.

Kitty [74]

It’s hard to see the image

7 0

3 years ago

Solve the inequality 2x - 5 \le -x +12. Give your answer as an interval.

ludmilkaskok [199]

Answer: $\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \frac{17}{3}\:\\ \:\mathrm{Decimal:}&\:x\le \:5.66666\dots \\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:\frac{17}{3}]\end{bmatrix}$

Step-by-step explanation:

$2x-5\le \:-x+12$

$2x\le \:-x+17\\$

$2x+x\le \:-x+17+x$

$3x\le \:17$

$\frac{3x}{3}\le \frac{17}{3}$

$x\le \frac{17}{3}$

6 0

3 years ago

Which equation represents the circle described? (in picture)

Sedaia [141]

You are right. In circle equation we have =r² so the correct answer will be C od D. But we have to calculate the center of a circle.

$x^2+y^2-8x-6y+24=0\quad|-24\\\\(x^2-8x)+(y^2-6y)=-24$

Complete the square:

$x^2-8x+a^2\implies a=\dfrac{8x}{2x}=4\implies x^2-8x+4^2\\\\\\y^2-6y+b^2\implies b=\dfrac{6y}{2y}=3\implies y^2-6y+3^2$

And we have:

$(x^2-8x)+(y^2-6y)=-24\\\\(x^2-8x+4^2)-4^2+(y^2-6y+3^2)-3^2=-24\\\\
(x-4)^2+(y-3)^2-16-9=-24\\\\(x-4)^2+(y-3)^2-25=-24\quad|+25\\\\\boxed{(x-4)^2+(y-3)^2=1}$

So the answer is C (the same left side of equation).

6 0

3 years ago

= Homework: Section 9.6

MA_775_DIABLO [31]

Answer:

here is an an example

Step-by-step explanation:

Let x = the width of the rectangle

P = 2l + 2w

2(40) + 2x ≤ 150

80 + 2x ≤ 150

2x ≤ 70

x ≤ 35 cm

7 0

3 years ago

Devin is investigating the relationship between the temperature in degrees Fahrenheit and the number of gallons sold at a lemona

Temka [501]

Answer:

d. A good line of best fit is y= 0.36x -20.15 because this is what the regression calculator returns if all the data except the point (86, 2) are entered. :)

Step-by-step explanation:

5 0

3 years ago

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