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Ray Of Light [21]
3 years ago
7

Write the ratio 2/3 /5 in simplest form

Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0

Answer:

A) 2/15

Step-by-step explanation:

So just divide it normally, do keep change flip

2/3*1/5

2/3 keep

divison change

Denomeinator, flip it, 5 to 1/5

now multiply

2/15

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Select the solid whose cross sections are dilations of some two-dimensional shape using a point directly above the shape as a ce
s2008m [1.1K]

Answer:

Cone

Step-by-step explanation:

Options:

a) Cone      b)  Cube     c)  Cylinder    d)  Triangular prism

From the given options (a) to (d), option (a) is true.

This is so, because.

The volume (V) of a cone  is:

V_1 = \frac{1}{3}\pi r^2h

This is as a result of dilating the cylinder by 1/3 whose volume is:

V_2 = \pi r^2h

In other words:

V_1 = \frac{1}{3}V_2

<em>i.e. the cross-section of the cylinder (V2) being dilated by 1/3 (which is between 0 and 1) gives the cone (V1)</em>

6 0
3 years ago
Which ordered pair is a solution of the equation? 7x-2y=-5
saul85 [17]

answer X= 5 over 7 and 2 over 7y step by step explaination add 2y on both sides u cancelled -2y and positive 2y u bring down 7X u get 7X=-5+3 then u divide and u get that answer yw have a nice day mark me brainliest

8 0
3 years ago
Read 2 more answers
Cellus
Paladinen [302]

Answer:

9/4

Step-by-step explanation:

The quadratic function can be rearranged to look like this:

x^2-3x-1=0

Now we see that the constant b is equal to -3. Using the hint, we find:

(-3/2)^2=9/4

Hope that helps!

4 0
3 years ago
Look down<br> Also show your work <br><br> "as the teacher say
dimulka [17.4K]
Good Job
And always keep your eyes on ur own paper
6 0
2 years ago
Read 2 more answers
3x²-9x+1+0 Find the discriminant
Sindrei [870]

Answer:

\boxed{D = 69}

Step-by-step explanation:

The given quadratic equation is:

3x^2-9x+1 = 0

Comparing it with the standard form of Quadratic Equation ax^2+bx+c = 0 , we get:

a = 3, b = -9 and c = 1

Discriminant = b² - 4ac

D = (-9)²-4(3)(1)

D = 81 - 12

D = 69

3 0
3 years ago
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