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skad [1K]
3 years ago
5

Need help fast thanks

Mathematics
1 answer:
Katena32 [7]3 years ago
8 0

Answer:

Have no idea..

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What is the value of x?<br><br> Enter your answer, as a decimal, in the box.<br><br> cm
kirza4 [7]

Answer:

50.6 cm

Step-by-step explanation:

We can use similar triangles and proportions to solve.  Put the smaller triangle side over the larger triangle side.

x               46.2-14   (This is the length of the short side of the triangle)

--------- = -------------

72.6            46.2

Using cross products

46.2 *x = (46.2-14)  *72.6

46.2 *x = (32.2)  *72.6

46.2 *x = (32.2)  *72.6

46.2x =2337.72

Divide each side by 46.2

46.2/46.2 *x = 2337.72/46.2

x = 50.6

5 0
3 years ago
Sarah stands at the corner of a rectangular field. If the field measures 180 m by 210 m, how far would Sarah need to walk to
Agata [3.3K]

Answer:

30√85 or 276.5863 meters

Step-by-step explanation:

Use pythag theorom. a^2+b^2=c^2

180^2+210^2=c^2

c=276.5863

4 0
2 years ago
If Jeremy drinks 1 1/2 quarts of coffee every 3 days, how many liters of coffee would Jeremy drink in 3 weeks? (1 quart = 0.946
Nostrana [21]

Answer:

9.93 liter approximately 10 liter

Step-by-step explanation:

3 days = 3/2 quart

3 week = 3/2/3 × 21 quarts

= 1/2×21

=21/2 quarts

now

1 quart = 0.946 liter

21/2 quart = 0.946×21/2 liter

21/2 quart = 9.93 liter

8 0
2 years ago
A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the
Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of​ metal

y ----> the original width of the piece of​ metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in

The volume of the box is equal to

V=(x-10)(y-10)5

V=930\ in^3

so

930=(x-10)(y-10)5

simplify

186=(x-10)(y-10) -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

so

x=y+25 ----> equation B

substitute equation B in equation A

186=(y+25-10)(y-10)

solve for y

186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

x=16+25=41

therefore

The original length was 41 inches and the original width was 16 inches

3 0
3 years ago
Help? pre cal, will give points
Viktor [21]

Steps to solve:

5x² = 15x

~Subtract 15x to both sides

5x² - 15x = 15x - 15x

~Simplify

5x² - 15x = 0

~Factor left side

5x(x - 3) = 0

~Factors equal 0

5x = 0 and x - 3 = 0

___________

~Simplify 5x = 0

5x/5 = 0/5

x = 0

~Simplify x - 3 = 0

x - 3 + 3 = 0 + 3

x = 3

___________

Thus, the correct answer is 0, 3.

___________

Best of Luck!

4 0
3 years ago
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