OK the problem is focusing on VOLUME and TIME.. you can set up this problem like this... (v1/t1) x (v2/t2). first we plug in what we know. the first container was filled in 4 minutes so this is our "T1". However we weren't giving the volume of the first container but we were given its dimensions. the volume formula is LxWxH. so we plug in 9x11x12 to get 1188. this is our "V1". the same concept applies for the volume of the aquarium. we have its dimensions so just plug in. 24x25x33 = 19800 this is our "V2". the thing we are left trying to find is T2. so now you can do some cross multiplying and division. (T1xV2)/V1 or (4x19800)/1188 and you get 66.67min or 1h and 6.67mins. and thats how long it took to fill the aquarium.
I guess the chef is making the mixture for the sheriff... Let <em>x</em> be the amount of dressing with 5% vinegar that is required, and <em>y</em> the amount of 15% vinegar dressing (both amounts in mL).
The sheriff wants 390 mL of the mixed dressing, so that
<em>x</em> + <em>y</em> = 390
<em>x</em> mL of the 5% dressing contains 0.05<em>x</em> mL of vinegar, while <em>y</em> mL of the 15% dressing contains 0.15<em>y</em> mL of vinegar. The resulting mixture should have a concentration of 9% vinegar, so that it contains 0.09 (390 mL) = 35.1 mL of vinegar. This means
0.05<em>x</em> + 0.15<em>y</em> = 35.1
Solve for <em>x</em> and <em>y</em> :
<em>y</em> = 390 - <em>x</em>
0.05<em>x</em> + 0.15 (390 - <em>x</em>) = 35.1
0.05<em>x</em> + 58.5 - 0.15<em>x</em> = 35.1
23.4 = 0.10<em>x</em>
<em>x</em> = 234
<em>y</em> = 156
Answer:
-8 • (6 + 3) + 390 + 6=324
Step-by-step explanation:
Answer:
-8x
Step-by-step explanation:
Subtract 6°x from -2x.
The volume of a square pyramid is (1/3)(area of base)(height of pyramid).
Here the area of the base is (10 ft)^2 = 100 ft^2.
13 ft is the height of one of the triangular sides, but not the height of the pyramid. To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft. That "middle" is 5 units straight down from the upper vertex. Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft). What is the height of the pyramid?
To find this, use the Pyth. Thm.: (5 ft)^2 + y^2 = (13 ft)^2. y = 12 ft.
Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
