Answer:
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Find the probability that the diameter of a selected bearing is greater than 85 millimeters.
This is 1 subtracted by the pvalue of Z when X = 85. Then



has a pvalue of 0.7486.
1 - 0.7486 = 0.2514
0.2514 = 25.14% probability that the diameter of a selected bearing is greater than 85 millimeters.
Answer:
× 
Step-by-step explanation:
500
= 2 x 250
= 2 x 10 x 25
= 2 x 2 x 5 x 5 x 5
=
× 
Answer:
Option 1
Step-by-step explanation:
-5/8, -1⅔, 0.8, ½
-5/8 = -0.625
-1⅔ is approximately -1.67
0.8
½ = 0.5
-1.67, -0.625, 0.5, 0.8
-1⅔, -⅝, ½, 0.8
Answer:
Step-by-step explanation:
Volume= (length)(width)(height)
step 1: make sure all the measurements have the same unit (ft)
step 2: convert mixed fractions to improper fractions
1 2/3= 5/3 1 1/6= 7/6 1 1/5 = 6/5
multiply the length by width and height
(5/3)(7/6)(6/5)
=7/3 ft^3