The 3rd one and the last one.
1727 remainder 4
I had to write out
Area of rectangular board = length (inches) x width (inches) = 12" x 16" = 192 in²
Area of the border is given as 128 in²
Adding the area of the board and the border gives (192 + 128)in² = 320 in²
Set this up as the algebraic equation (x + 12)(x + 16) = 320 and solve for x:
Remember to use the FOIL method, which is multiplying the terms in the order of first, outer, inner, last.
x² + 12x + 16x + 192 = 320
x² + 28x + 192 - 320 = 0
x² + 28x - 128 = 0
solve for the two x values:
(x + 32)(x - 4) = 0, and knowing we only need the positive x value
x = 4 or 4 inches is the width of the border
Answer:
1) 29
2) 64
you can use the explanation below to help find the other 6 problems
Step-by-step explanation:
1) 4(5+6) - 15 = 4 * 11 - 15 = 44 - 15 = 29
2) 8(2+4) + 16 = 8 * 6 + 16 = 48 + 16 = 64
You are given the information that he takes six lessons per week. First we will calculate the total lessons he could potentially take per year.
6 • 52 = 312
He could potentially take 312 lessons in one year.
Now that you know this information, you simply subtract the days he missed from that total.
312 - 5 = 307
Your final answer: Peter took 307 lessons during the year.
