Answer:
(a) 36.36%
(b) 0.36%
(c) 0.06%
Step-by-step explanation:
Given that the time intervals measured with a stopwatch have an uncertainty of about 0.2 s.
We want to know what is the percent uncertainty of a hand-timed measurement of:
(a) 5.5 s
Percentage = (0.2/5.5) × 100
≈ 36.36%
(b) 55 s
Percentage = (0.2/55)×100
≈ 0.36%
(c) 5.5 min
5.5 min = 5.5 × 60 s
= 330 s
Percentage = (0.2/330)×100
≈ 0.06%
Answer:
There were 16 ounces of Cat Food after 24 days.
Step-by-step explanation:
From the graph attached,
For an ordered pair (x, y) lying on the graph,
x-coordinate represents the number of days since bag was bought and y- coordinate represents the ounces of cat food required.
Now the value x = 24 on x-axis shows the number of days since the bag was bought.
For x = 24, ounces of cat food in the bag ( y ) = 16 ounce
Therefore, 16 ounces of Cat Food were in the bag after 24 days since it was bought.
Huw's answer of 9 days is incorrect because more guests would finish the food in less time so the number of days for 30 guests is less than 6 days.
The number of days that the food can last 30 guests is 4 days.
<h3>How long will Seaview Hotel's food feed 30 guests?</h3>
More guests would eat the food faster which means that it would be finished in less days than the 6 days used by 20 guests.
To find the days the food would last 30 guests, use the inverse proportion formula:
= (Number of guests x Number of days food lasts for guests) / New number of guests
= (20 x 6) / 30
= 4 days
Full question is:
The only food provided for guests at Seaview Hotel is breakfast. The hotel has enough food to make breakfast for 20 guests for 6 days. How long would the food last 30 guests? You may assume each guest eats the same amount of food for breakfast.
Without working out the correct answer, explain why Huw’s answer of 9 days is incorrect.
Find out more on inverse proportion at brainly.com/question/1266676.
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Answer:
3 9/10,64,B,D
Step-by-step explanation:
