R(p) = -15p² + 200p + 10,000
To find the maximum of the function, we take the first derivative and equate to 0:
R'(p) = -30p + 200
0 = -30p + 200
p = 6.67
A price of $6.67 will maximize revenue.
Answer:
Decrease
Step-by-step explanation:
If you look at the numbers in general 1.6 has a one in it. Meanwhile 0.95 is part of one. Think of it as money. Which would you rather have $1.60 or 0.95 cents.
Answer:
And if we count the number of zeros before the number 7, we can rewrite the number like this:
We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
Step-by-step explanation:
For this case we have the following number given:
And if we count the number of zeros before the number 7, we can rewrite the number like this:
We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
The answer is: " 5 (five) players " .
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(Note: We are given FIVE (5) values in the data set).
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Answer:
x=3
Step-by-step explanation: