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3 years ago

Calculate the initial value: m= 5 (-3, 6)

Mathematics

1 answer:

AysviL [449]3 years ago

4 0

Answer:

initial value is 21

Step-by-step explanation:

y=mx+b

6= -3(5) +b

b=21

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HELP PLZ FIRST ANSWER WILL GET BRAINLIEST<br> 5 5/6 times 4 1/4

Nikolay [14]

Hello!

It would be 24.79 but if the answer were to be rounded, it would be 25

Hope this helps! :)

6 0

2 years ago

Read 2 more answers

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

3 years ago

Anvisha [2.4K]

You can obtain the a number for which they all divisors by calculating the least common multiple.

This way:

85 = 5*17*1
17=17*1
19=19*1
4=2^2 *1
2=2*1

The least common multiple is: 5*17*19*2^2 = 6,460.

Then 84, 17, 19, 4 and 2 are all divisors of 6,460.

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3 years ago

In ΔABC shown below, ∠BAC is congruent to ∠BCA: Triangle ABC, where angles A and C are congruent Given: Base ∠BAC and ∠ACB are c

Morgarella [4.7K]

1. Definition of bisector
2. ASA congruence theorem or ASA Postulate

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3 years ago

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PLEASE HELP THIS IS A MAJOR GRADE! In the diagram below, triangle DEF is a translation of triangle ABC.

Marizza181 [45]

Answer:

2 units right and 5 units down

3 0

3 years ago