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Helen [10]
3 years ago
13

The sum of two numbers is 51. The larger number is 17 more than the smaller number. What are the numbers ?

Mathematics
1 answer:
Serggg [28]3 years ago
4 0

Answer:

The numbers are 17 and 34.

Step-by-step explanation:

I just subtracted 17 from 51, it equals 34, and 34 is 17 more than 17. Add 34 and 17 and you get 51.

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42x+25y=486, x+y=14<br>show work please help asap!​
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Rewrite equations:
x+y=14;42x+25y=486

Step: Solvex+y=14for x:
x+y=14
x+y+−y=14+−y(Add -y to both sides)
x=−y+14

Step: Substitute−y+14forxin42x+25y=486:
42x+25y=486
42(−y+14)+25y=486
−17y+588=486(Simplify both sides of the equation)
−17y+588+−588=486+−588(Add -588 to both sides)
−17y=−102
−17y
−17
=
−102
−17
(Divide both sides by -17)
y=6

Step: Substitute6foryinx=−y+14:
x=−y+14
x=−6+14
x=8(Simplify both sides of the equation)

On Fri, Sep 20, 2019 at 12:08 PM ESQULESE BLACK wrote:

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3 years ago
The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.
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Answer:

A sample of 179 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.85}{2} = 0.075

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.075 = 0.925, so Z = 1.44.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

A previous study found that for an average family the variance is 1.69 gallon?

This means that \sigma = \sqrt{1.69} = 1.3

If they are using a 85% level of confidence, how large of a sample is required to estimate the mean usage of water?

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M = z\frac{\sigma}{\sqrt{n}}

0.14 = 1.44\frac{1.3}{\sqrt{n}}

0.14\sqrt{n} = 1.44*1.3

\sqrt{n} = \frac{1.44*1.3}{0.14}

(\sqrt{n})^2 = (\frac{1.44*1.3}{0.14})^2

n = 178.8

Rounding up

A sample of 179 is needed.

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