Okay, first we need to figure out what one would make. We need to figure out the area of the base x height. The diameter is 8 so we will cut that to 4 so we can do piR2! 3.14x16 would be 50.24. Then we mutiply that by 10 to get 502.4cm3! Okay, now we would divide 2000/502.4 to find out how many times we would have to make the containers to get to 2000. The answer is 3.98, which we will have to round up since its asks for the minimum and you cant make a container 3.98 times. So the answer is 4!
Answer:
-3
Step-by-step explanation:
We want (n/p)(1). We can obtain this by finding n(1) and p(1) and then dividing as indicated:
p(1) = 3(1) - 2 = 1
n(1) = 2(1) - 5 = -3
Then (n/p) (1) = -3/1, or just -3
218.16 to the nearest tenth would be 218
Original:
<span>The width and length of a rectangle are consecutive odd integers
</span>so W = x and L = x + 2
<span>If the length is increased by 5 feet, then new L = x + 2 + 5 = x + 7
</span>
A = L x W
60 = (x + 7) x
60 = x^2 + 7x
x^2 + 7x - 60 = 0
(x - 5)(x + 12) = 0
x = 5 and x = -12
From here you have x = W = 5 ft and L = x + 2 = 5 + 2 = 7 feet
Area of original = 5 x 7 = 35
answer
<span>the area of the original rectangle: </span>35 ft^2
