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Arada [10]
2 years ago
14

N = 9

Mathematics
1 answer:
g100num [7]2 years ago
7 0

Answer:

The <em>p</em>-value is 0.809.

Step-by-step explanation:

In this case we need to perform a significance test for the standard deviation.

The hypothesis is defined as follows:

<em>H</em>₀: <em>σ</em>₀ = 4 vs. <em>Hₐ</em>: <em>σ</em>₀ ≤ 4

The information provided is:

<em>n</em> = 9

<em>s</em> = 3

Compute the Chi-square test statistic as follows:

\chi^{2}=\frac{(n-1)s^{2}}{\sigma_{0}^{2}}

     =\frac{(9-1)\cdot (3)^{2}}{(4)^{2}}\\\\=\frac{8\times 9}{16}\\\\=4.5

The test statistic value is 4.5.

The degrees of freedom is:

df = n - 1

   = 9 - 1

   = 8

Compute the <em>p</em>-value as follows:

p-value=P(\chi^{2}_{9}>4.5)=0.809

*Use a Chi-square table.

Thus, the <em>p</em>-value is 0.809.

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