Question

Solve x^2- 2x - 4 = 0

Answer 1

Answer:

$\displaystyle x= 1\pm \sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Standard Form: ax² + bx + c = 0
• Quadratic Formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

Step 1: Define

x² - 2x - 4 = 0

Step 2: Identify Variables

a = 1

b = -2

c = -4

Step 3: Solve for x

1. Substitute [QF]:                    $\displaystyle x=\frac{2\pm\sqrt{(-2)^2-4(1)(-4)} }{2(1)}$
2. Exponents:                           $\displaystyle x=\frac{2\pm\sqrt{4-4(1)(-4)} }{2(1)}$
3. Multiply:                                $\displaystyle x=\frac{2\pm\sqrt{4+16} }{2}$
4. Add:                                      $\displaystyle x=\frac{2\pm\sqrt{20} }{2}$
5. Simplify:                               $\displaystyle x=\frac{2\pm 2\sqrt{5} }{2}$
6. Factor:                                 $\displaystyle x=\frac{2(1\pm \sqrt{5}) }{2}$
7. Divide:                                 $\displaystyle x= 1\pm \sqrt{5}$

Answer 2

Answer:

yes

Step-by-step explanation: