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FrozenT [24]
3 years ago
5

Solve 3(5x-4) < 15x

Mathematics
2 answers:
Vaselesa [24]3 years ago
7 0
The answer is D. All real numbers
ollegr [7]3 years ago
5 0

Answer:

All real numbers

Step-by-step explanation:

3(5x - 4) < 15x

~Distribute left side

15x - 12 < 15x

~Subtract 15x to both sides

-12 < 0

Best of Luck!

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Any equation can be written in function notation<br> O True<br> False
Fynjy0 [20]

Answer: True

Step-by-step explanation:

7 0
3 years ago
Please help! Brainliest to correct.
Margarita [4]

Answer:

We are given the following in the question:

where P(x) in millions is the number of U.S. travelers from 1990 through 2009 and x = 1 represents 1991.

We have to approximate the number of U.S. travelers to other countries in each given year.

​(a) 1990

We put x = 0 in the given function.

Thus, there are 48.09 millions U.S. travelers in 1990.

​(b) 2000

We put x = 10 in the given function.

Thus, there are 56.888 millions U.S. travelers in 2000.

​(c) 2009

We put x = 19 in the given function.

Thus, there are 31.085 millions U.S. travelers in 2009.

Step-by-step explanation:

Hope this helps:) plz mark as brainliest I really need it:)

7 0
3 years ago
The price of Stock A at 9 A.M. was ​$14.65. Since​ then, the price has been increasing at the rate of ​$0.13 each hour. At noon
Nataly [62]

Answer:

The prices of the two stocks will be the same in 1.56 hours.

 

The price of Stock A at 9 A.M. was ​$12.95 Since​ then, the price has been increasing at the rate of ​$0.12 each hour.

This means that after x hours, the value of Stock A is:

After noon:

Noon is 3 hours after 9 AM, so

So in x hours after noon, the value is given by:

At noon the price of Stock B was ​$13.70. It begins to decrease at the rate of ​$0.13 each hour.

This means that after x hours, the value of Stock B is:

In how many hours will the prices of the two stocks be the​ same?

This is x for which:

The prices of the two stocks will be the same in 1.56 hours.

Step-by-step explanation:

Hope this helps:)

5 0
2 years ago
Read 2 more answers
D/d{cosec^-1(1+x²/2x)} is equal to​
SIZIF [17.4K]

Step-by-step explanation:

\large\underline{\sf{Solution-}}

\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg)

Let assume that

\rm :\longmapsto\:y =  {cosec}^{ - 1} \bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg)

We know,

\boxed{\tt{  {cosec}^{ - 1}x =  {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}

So, using this, we get

\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 +  {x}^{2} } \bigg)

Now, we use Method of Substitution, So we substitute

\red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z =  {tan}^{ - 1}x}

So, above expression can be rewritten as

\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 +  {tan}^{2} z} \bigg)

\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)

\rm\implies \:y = 2z

\bf\implies \:y = 2 {tan}^{ - 1}x

So,

\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x

Thus,

\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg)

\rm \:  =  \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)

\rm \:  =  \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)

\rm \:  =  \: 2 \times \dfrac{1}{1 +  {x}^{2} }

\rm \:  =  \: \dfrac{2}{1 +  {x}^{2} }

<u>Hence, </u>

\purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 +  {x}^{2} }{2x} \bigg) =  \frac{2}{1 +  {x}^{2} }}}}

<u>Hence, Option (d) is </u><u>correct.</u>

6 0
2 years ago
Given the figure below, find the values of x and z.<br> X=<br> Z=<br> (11x - 93)<br> H<br> 116<br> X
Marrrta [24]

Answer:

x = 19

z = 64

Step-by-step explanation:

Angles (11x - 93)° and 116° are vertical angles, so their measures are equal.

11x - 93 = 116

11x = 209

x = 19

Angles z° and 116° are a linear pair, so they are supplementary, and their measures have a sum of 180°

z + 116 = 180

z = 64

6 0
1 year ago
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