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3 years ago

What percent is 54 of 60

Mathematics

2 answers:

serg [7]3 years ago

6 0

90% would be your answer.

Alex787 [66]3 years ago

4 0

54-60 is 90 percent because 54÷60= 0.9=90

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What does the symble for a fraction

Nuetrik [128]

Answer:

I don't understand the question

Step-by-step explanation:

6 0

3 years ago

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If EG=19 and FG=12 then EF=?

Volgvan

Answer:

EF = 31

Step-by-step explanation:

Note that in both line segments (EG & FG), they both have point G in them. This means that point G is the shared point and the mid-point. Add the two line segments together to get the full segment.

EG + FG = EF

19 + 12 = 31

31 is your answer

3 0

3 years ago

What is the minimum value of the function g (2) = x2 - 6x – 12? -21 3+ V21 3 3-21

kirill [66]

Answer:

g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12? g (2) = x2 - 6x – 12?

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The length of a side of a triangle is 36. A line parallel to that side divides the triangle into two parts of equal area. Find t

pantera1 [17]

Answer:

18√2

Step-by-step explanation:

The area of the smaller triangle is 1/2 that of the larger one. Since the triangles are similar, the dimensions of the smaller triangle are √(1/2) those of the larger one.

36 · √(1/2) = 36 · (√2)/2 = 18√2 . . . . length of line dividing the triangle

6 0

4 years ago

If logb2=x and logb3=y, evaluate the following in terms of x and y:

Alja [10]

$log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x$

Solution:

Given that,

$log_b2 = x\\\\log_b3 = y --------(i)$

Use the following log rules

Rule 1: $log_b(ac) = log_ba + log_bc$

Rule 2: $log_b\frac{a}{c} = log_ba - log_bc$

Rule 3: $log_ba^c = clog_ba$

$a) log_b{162}$

Break 162 down to primes:

$162 = 2^1 \times 3^4$

$log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y$

Thus we get,

$log_b162 = x + 4y$

$b) log_b 324$

Break 324 down to primes:

$324 = 2^2 \times 3^4$

$log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y$

$c) log_b\frac{8}{9}$

By rule 2

$log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} = 3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} = 3x - 2y$

$d) \frac{log_b27}{log_b16}$

By rule 2

$\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} = 3y - 4x$

Thus the given are evaluated in terms of x and y

3 0

3 years ago