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goldenfox [79]
3 years ago
7

Which equation describes this line?

Mathematics
1 answer:
yawa3891 [41]3 years ago
3 0

Answer:

The equation of line with given points is  y - 4 = 3 ( x + 2 ) .

Step-by-step explanation:

Given as :

The points of line are ( 1 , 13 )   and    ( - 2 , 4 )

The point slope intercept equation of line is

y - y_1 = m ( x -  x_1 )

Where m is the slope of line

So , Slope , m = \frac{y_2 - y_1}{x_2 - x_1}

Or, m =  \frac{4 - 13}{ - 2 - 1}

Or, m =  \frac{ - 9}{ - 3}

∴    m = 3

Now The equation of line is

y - y_1 = m ( x -  x_1 )

Or. y - 13 = 3 ( x -  1 )

Or, y - 13 = 3 x - 3

Or, y = 3 x - 3 + 13

∴   y = 3 x + 10

I.e y - 4 = 3 x + 6

Or, y - 4 = 3 ( x + 2 )

Hence The equation of line with given points is  y - 4 = 3 ( x + 2 ) . Answer

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Answer:

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Step-by-step explanation:

Hi there!

We are given the line segment, with the end points AB

The coordinates of A are (-5, -4), and the coordinates of B are (-3, 3).

We want to find the midpoint of the line segment AB

The midpoint formula is given as (\frac{x_1+ x_2}{2}, \frac{y_1 + y_2}{2}), where (x_1, y_1) and (x_2, y_2) are coordinates

We have two coordinates, which is what we need, but let's label their values to avoid any confusion:

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Now simplify the numerator and denominator

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Simplify again:

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Hope this helps!

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