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2 years ago

15

What is the solution to the system of equations graphed below?

2 answers:

Soloha48 [4]2 years ago

5 0

Short Answer B
Remark
You need not do any calculations to get the answer. You are required just to read the graph. Doing the calculations would be beneficial but unnecessary.

Step One
Find the x value.
1. If you have a ruler or a straight edge of some kind, put it on the cross point of the two graphs.
2. Make the ruler go straight up and down. You will find out it goes 1 point back of the 5.
3. Count the number of squares from 0,0 or when y = 0.
4. You will find you have to count 4 squares along the x axis.

The x value is 4.

Step Two
1. Put the ruler on the cross point again. This time make it go straight across.
2. Count up from (0,0)
You should get 8.

The y value is 8

Answer: (4,8)

melomori [17]2 years ago

4 0

The answer is (4,8)

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2 years ago

Jenna is drawing a sketch of her room. The room is 15 feet long by 12 feet wide. The

SOVA2 [1]

Answer:

4 inches

Step-by-step explanation:

Actual dimensions:

Length = 15 feet

Width = 12 feet

Scale dimensions:

Length = 5 inches

Width = x inches

Write a proportion:

$\dfrac{\text{Actual length}}{\text{Scale length}}=\dfrac{\text{Actual width}}{\text{Scale width}}\\ \\ \\\dfrac{15\ feet}{5\ inches}=\dfrac{12\ feet}{x\ inches}\\ \\x=\dfrac{5\ inches\times 12\ feet}{15\ feet}=4\ inches$

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3 years ago

PQR is a right angled triangle calculate the size of angle marked x

romanna [79]

Answer:

$\displaystyle x \approx 37.4^\circ$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality<u> </u>

<u>Trigonometry</u>

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] cosθ = adjacent over hypotenuse<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

Angle θ = <em>x</em>

Adjacent Leg = 5.8

Hypotenuse = 7.3

<u>Step 2: Solve for </u><em><u>x</u></em>

Substitute in variables [Cosine]: $\displaystyle cosx^\circ = \frac{5.8}{7.3}$
[Fraction] Divide: $\displaystyle cosx^\circ = 0.794521$
[Equality Property] Trig inverse: $\displaystyle x^\circ = cos^{-1}(0.794521)$
Evaluate trig inverse: $\displaystyle x = 37.39^\circ$
Round: $\displaystyle x \approx 37.4^\circ$

8 0

2 years ago

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

<u></u> $\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

<u></u> $\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

2 years ago