The question is so dry, mechanical, and devoid of emotion
that it's terrifying.
There is no way to assign a number to "How many people were
dying per day", and I would prefer not even to think about it in
those terms.
-- The period of time from August 4, 1914 until November 11, 1918 is 1,560 days.
-- The "average", or better, the "unit rate" of 10 million events in 1,560 days
is the quotient
(10,000,000 events) / (1,560 days)
= 6,410.3 events per day
= 267.1 events per hour
= 4.45 events per minute.
Reciprocally, this is a unit rate of
13.48 seconds per event,
sustained continuously for 4.274 years !
When will we ever learn ! ?
very simple, we use the formula sin(a+b)=sinacosb +
sinbcosa and sin(20)=2sinacosa
5pi = 2pi/3+3pi/3,
First, we use sin(a+b)=sinacosb + sinbcosa
sin(5pi/3)=sin(2pi/3+3pi/3)=
sin(2pi/3+pi)=
sin(2pi/3)cos(pi) +sin(pi)cos(2pi/3)
but we know that sin(pi)=
0, and cos (pi) = -1, so sin(5pi/3)=
- sin(2pi/3)
now, use sin(2a)=2sinacosa,
sin(5pi/3)= - sin(2pi/3)= -2sin(pi/3)cos(pi/3)
sin<span>(5pi/3)=
-2sin(pi/3)cos(pi/3)</span>
<span>sin(pi/3)= 0.86,
cos(pi/3)=0.5, finally we have </span>sin<span>(5pi/3)= -0.86 x 0.5= -0.43</span>
71.1538462 rounds to 72% the answer is 72%
Answer:
60+14=p
Step-by-step explanation:
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