In which quadrant does the point (13, 18) lie

Mathematics

1 answer:

Dahasolnce [82]3 years ago

8 0

Answer:

Quadrant 1

Step-by-step explanation:

how I understood this is first understanding how a graph works. Once you understand that you can count 13 horizontal on the "X" Axis, then go 18 up on the "Y" axis. you should get a point in the upper left area and that area is called Quadrant 1. Say if 13 was negative instead of going horizontal east you would go horizontal west. And the point should end up in Quadrant 2. Any more questions feel free to ask me below.

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If a number n has exactly 7 divisors, how many divisors does n squared have?

Anna [14]

A number $n=p_1^{a_1}\cdot p_2^{a_2}\cdot\ldots\cdot p_k^{a_k}$ , where $p_k$ are distinct prime numbers, has $(a_1+1)(a_2+1)\cdot\ldots\cdot(a_k+1)$ divisors.

We know that $n$ has 7 divisors. 7 is a prime number, so among the numbers $a_1+1,a_2+1,\ldots,a_k+1$ there is only one that is equal to 7.

So,
$a_k+1=7\\
a_k=6$

That means $n=p^6$ where $p$ is a prime number.
$n^2=(p^6)^2=p^{12}$ , therefore the $n^2$ has $12+1=13$ divisors.

4 0

3 years ago

Simply -3 3/4 divided by 2 1/2

Dima020 [189]

Answer:

$=-1\frac{1}{2}$

Step-by-step explanation:

Given the following question:

$-3\frac{3}{4} \div2\frac{1}{2}$

In order to find the answer, we first convert the mixed numbers into improper fractions. Then we use KCF (Keep, Change, Flip) and solve.

$-3\frac{3}{4} \div2\frac{1}{2}$
$-3\frac{3}{4} =12+3=-\frac{15}{4}$
$2\frac{1}{2}=2\times2=4+1=\frac{5}{2}$
$-\frac{15}{4} \div\frac{5}{2}$
$-\frac{15}{4} \times\frac{2}{5}$
$15\times2=30$
$4\times5=20$
$=-\frac{30}{20}$
$-\frac{30}{20} \div10=-\frac{3}{2}$
$-\frac{3}{2}=3\div2=-1\frac{1}{2}$
$=-1\frac{1}{2}$

Hope this helps.